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jeka57 [31]
3 years ago
7

What is the percent for $5 off $886.20?

Mathematics
1 answer:
agasfer [191]3 years ago
8 0
5/886.20 * 1000 = 0.564206725344166 %
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A truck left a station at 6:00am traveling at a rate of 45km/h. A van left the same place 2 hours later heading in the same dire
OverLord2011 [107]

The Van would catch up with the truck at 6:00 pm

Speed is the ratio of distance travelled to time taken. It is given by:

Speed = distance / time

Let us say the van catch up with the truck after t hours at a distance d.

For the truck:

45 = d/t

d = 45t

For the Van:

54 = d / (t - 2)

d = 54t - 108

45t = 54t - 108

9t = 108

t = 12 hours

The Van would catch up with the truck at 6:00 pm

Find out more on speed at: brainly.com/question/3004254

6 0
2 years ago
Read 2 more answers
Help me please ASAP
Mashutka [201]

Answer: \frac{5}{35}

Step-by-step explanation:

Since, the total number of contestant = 7,

Thus, the probability that out of 3 contestant, me and my friend is chosen

= \frac{2_C_2\times 5_C_1}{7_C_3}

= \frac{\frac{2!}{2!0!}\times \frac{5!}{1!\times 4!}}{\frac{7!}{4!\times 3!}}

= \frac{1\times 5}{\frac{7\times 6\times 5\times 4!}{4!\times 6}}

=  \frac{5}{35}

⇒ Third Option is correct.

4 0
3 years ago
Cos^(2)x=(cscxcosx)/(tanx+cotx)
bixtya [17]
\cos^2 x = \dfrac{\csc x \cos x}{\tan x + \cot x}

\cos^2 x = \dfrac{\csc x \cos x}{\dfrac{\sin x}{\cos x} + \dfrac{\cos x}{\sin x}}

\cos^2 x = \dfrac{\csc x \cos x}{\frac{\sin x}{\cos x} \times 
\frac{\sin x}{\sin x} + \frac{\cos x}{\sin x} \times \frac{\cos x}{\cos 
x}}

\cos^2 x = \dfrac{\csc x \cos x}{\frac{\sin^2 x}{\sin x \cos x} + \frac{\cos^2 x}{\sin x \cos x}}

\cos^2 x = \dfrac{\csc x \cos x}{\frac{1}{\sin x \cos x}}

\cos^2 x = \csc x \cos x \sin x \cos x

\cos^2 x = \dfrac{1}{\sin x} \cos x \sin x \cos x

\cos^2 x = \cos^2 x
6 0
3 years ago
The function C(x)=600x-0.3x^2 represents the total costs for a company to produce a product, where C is the total cost in dollar
tatiyna
C(x)=- 0.3x^2+600x
y=ax^2+bx+c
it shows a upside down parabola equation.
to find maximum value we need to find its vertex(h,k)
as this is a standard quadratic equation we need to see parabolis equation too
y=a(x-h)^2+k
if u see this eq^n K would be the maximum value of Y if x=h.
  where h,k are vertex of parabola.

h=-b/2a(derived standard formula)
C(x)=- 0.3x^2+600x
y=ax^2+bx+c
a= -0.3 b=600
h=-600/-0.3
h= 2000
put h in place of x to get K
K= -0.3(2000)^2+600(2000)
K= - 1200000+1200000
K=0

u gets k=0
means C(x)=0
600x= -0.3x^2
600= 0.3x
x=6000/3
x= 2000 units


8 0
3 years ago
Read 2 more answers
Which values of a and b make the equation true?
zimovet [89]

Answer:

a=3

b=3

Step-by-step explanation:

(2xy)^4

----------------

4xy

Expand the numerator

2^4 x^4 y^4

---------------------

4xy

Simplify

16 x^4 y^4

---------------------

4xy

We know that a^b / a^c = a^(b-c)

16/4 * x^(4-1)  y^(4-1)

4 x^3 y^3

5 0
2 years ago
Read 2 more answers
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