Which range contains the value of sqrt(25-4+16)?

Mathematics

1 answer:

Olin [163]3 years ago

5 0

Answer:

I wanna say C. But I'm not exactly sure.

Step-by-step explanation:

I hope it's right :(

You might be interested in

1. Charlene makes $10 per hour babysitting and $5 per hour gardening. This week, she wants to make at least $80.

Lady_Fox [76]

Answer:

Step-by-step explanation:

Well is she wanted to make $80 “b” she would have to garden for 16 hours to make a maximum of $80

“C” if she wanted to make it out of babysitting she would have to work the same for 8 hours if she babysit

Workout : b part = 10+10+10+10+10+10+10+10 Key:10=2

:c part = 20+20+20+20. Key:20=2

Sorry I didn’t do a but just add all the things above and u get your answer

4 0

2 years ago

Adding the fractions<br><br> 3/14+2/21+1/6

NARA [144]

Answer:

$\frac{10}{21}$

Step-by-step explanation:

The LCM of 14, 21 and 6 is 42

We require to change the fractions to fractions with a denominator of 42

$\frac{3(3)}{14(3)}$ + $\frac{2(2)}{21(2)}$ + $\frac{1(7)}{6(7)}$

= $\frac{9}{42}$ + $\frac{4}{42}$ + $\frac{7}{42}$ ← add the numerators, leaving the denominator

= $\frac{9+4+7}{42}$

= $\frac{20}{42}$ ← divide both values by 2

= $\frac{10}{21}$ ← in simplest form

6 0

3 years ago

Ignore circled one and work it out please

mash [69]

Answer:

a. $\frac{(x-7)}{x^2+x-30}$

Step-by-step explanation:

$\huge \frac{x^2-3x-28}{(x^2+10x+24)(x-5)} \\\\\huge {=\frac{x^2-7x+4x-28}{(x^2+6x+4x+24)(x-5)}}\\\\\huge {=\frac{x(x-7)+4(x-7)}{\{x(x+6)+4(x+6)\}(x-5)}}\\\\\huge {=\frac{(x-7)(x+4)}{(x+6)(x+4)(x-5)}}\\\\\huge {=\frac{(x-7)}{(x+6)(x-5)}}\\\\\huge {=\frac{(x-7)}{x^2+(6-5)x+6(-5)}}\\\\\huge {=\frac{(x-7)}{x^2+x-30}}$