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stealth61 [152]
3 years ago
12

These plots show the number of kilometers a group of students at Middleton Middle School and at Westwood Middle School travel to

get to school each day. Number of Kilometers Middleton and Westwood Students Travel to School 2 dot plots. Both number lines go from 0 to 10. Plot 1 is titled Middleton. There is 1 dot above 1, 4 dots above 2, 5 dots above 3, 4 dots above 4, 4 dots above 5, 1 dot above 6, 0 dots above 7, 0 dots above 8, 1 dot above 9, 0 dots above 10. Plot 2 is titled Westwood. There are 0 dots above 0, 0 dots above 1, 4 dots above 2, 5 dots above 3, 4 dots above 4, 4 dots above 5, 3 dots above 6, and 0 dots above 7, 8, 9, and 10. The shapes of which plots, if any, show an outlier? both Middleton and Westwood Middleton only Westwood only neither Middleton nor Westwood
Mathematics
2 answers:
Irina-Kira [14]3 years ago
5 0

Answer:

middleton only

Step-by-step explanation:

took the test

vitfil [10]3 years ago
4 0

Answer:

<u>Middleton only</u>

Step-by-step explanation:

Sometimes, in a data set, there is a number that is much larger or much smaller than the others generally tend to be. These numbers that are far away from the average are known as outliers

The data set for the students at Middleton Middle School:

1 2 2 2 2 3 3 3 3 3 4 4 4 4 5 5 5 5 6 9

We can note that most of data is between 1 and 6, the gap between them is 0 or 1, but there is one of the data which is 9, the gap between 9 and 6 is 3

<u>So, 9 would be considered an outlier.</u>

<u>So, The shapes of plots shows an outlier is Middleton only</u>

The data set for the students at Westwood Middle School:

2 2 2 2 3 3 3 3 3 4 4 4 4 5 5 5 5 6 6 6

We can note that all of data is between 2 and 6, the gap between them is 0 or 1

<u>So, There is no outlier for the set of data.</u>

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Answer:

2

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The probability that Barry Bonds hits a home run on any given at-bat is 0.16, and each at-bat is independent.
serious [3.7K]

Answer:

a) 0.0797 = 7.97% probability that the next home run will be on his fifth at-bat.

b) The expected number of at-bats until the next home run is 6.25.

Step-by-step explanation:

For each at bat, there are two possible outcomes. Either it is a home run, or it is not. The probability of an at bat resulting in a home run is independent of any other at-bat, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

The probability that Barry Bonds hits a home run on any given at-bat is 0.16

This means that p = 0.16

Part A: What is the probability that the next home run will be on his fifth at-bat?

0 on his next 4(P(X = 0) when n = 4)

Home run on his 5th at-bat, with 0.16 probability. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{4,0}.(0.16)^{0}.(0.84)^{4} = 0.49787136&#10;

0.49787136 *0.16 = 0.0797.

0.0797 = 7.97% probability that the next home run will be on his fifth at-bat.

Part B: What is the expected number of at-bats until the next home run?

The expected number of trials for n successes is given by:

E = \frac{n}{p}

In this question, n = 1, p = 0.16. So

E = \frac{1}{0.16} = 6.25

The expected number of at-bats until the next home run is 6.25.

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