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zepelin [54]
3 years ago
15

5. A moth has two alleles for spots. It can have brown or white spots. The white allele is recessive and

Biology
1 answer:
WARRIOR [948]3 years ago
3 0

Answer:

0.7.5

Explanation:

I hope this is right

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A cell must expend energy to transport substance using
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The cell will use Endocytosis
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4 years ago
The following Punnett Square is a monohybrid cross. It takes the genotypes of the parents and predicts the genotypes of their of
Aleonysh [2.5K]

Answer:

For the 1st block on the left I think there are 2 dominants for that would be BB. The 1st block on the right would be 1 dominant and 1 recessive and that would be Bb. The bottom on the left would be the same as the first block on the right. That would be Bb. The last block that would be the bottom right would be 2 recessives and that would be bb. I hope this might help.

Explanation:

When you are doing punnet squares, you have dominant and recessive traits. There are ways you can do that. If you have 2 alleles of each parent of that offspring, there will be a genotype and a phenotype that represents a genetic trait of each genotype. I hope this helps your question.

4 0
3 years ago
A unique characteristic of birds is that they have _____.
umka21 [38]

Answer:

they can fly , which requires alot of energy & keep their body warm with their feathers

8 0
3 years ago
Give two reasons of the modification of stem of a plant in different forms,
vodka [1.7K]
1.underground stem -- for storage of food ex. potato , ginger.

2.spines for protection ex. citrus , bougainvillea
4 0
3 years ago
The frequency of autosomal alleles K and k in a large population of snails is 0.6 and 0.4. What is the approximate genotypic fre
Flura [38]

Answer:

Option (b).

Explanation:

The frequency of alleles K and k in population are 0.6 and 0.4. The inbreeding coefficient is 0.3.

The heterozygote frequency can be calculated by the formula:

F = \frac{2Kk-H}{2Kk}

Here, K = 0.6, k= 0.4, F = 0.3 and H = approximate genotypic frequency of heterozygote Kk.

Put the values in the above formula

0.3 = \frac{2\times2\times0.6\times0.4-H}{2\times0.6\times0.4}

H = 0.36 ≈ 0.34.

Thus, the approximate genotypic frequency of the heterozygote Kk is 0.34.

Hence, the correct answer is option (b).

5 0
3 years ago
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