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Papessa [141]
3 years ago
11

The volume of a cube is 27 cubic inches. What is the side length of the cube?

Mathematics
2 answers:
Galina-37 [17]3 years ago
7 0

Answer:

a=3in

Step-by-step explanation:

Using the formula

V=a^3

Solving for a

a=V⅓=27⅓=3in

oksano4ka [1.4K]3 years ago
5 0

Answer:

A. 3

Step-by-step explanation:

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Work out the volume of this prism.
a_sh-v [17]

Answer:

840

Step-by-step explanation:

Lets split the shape in 2 shapes which gives us 2 rectangular prisms

1st shape is the one stcking upward: 12*5*6=360

2nd shape: (we must subtract 5 from 15 because we used that for the other shape and hat wouldn't give us the correct answer) 10*8*6=480

480+360=

840

8 0
4 years ago
Lexi operates an orange juice stand. On Monday she used 4 bags of oranges. On Tuesday she used 1/2 as many oranges as on Monday.
Brut [27]
2 bags of oranges, 4/2=2
4 0
3 years ago
Can someone help me please
navik [9.2K]

Answer:

the \: answer \: is \: choice \: b \:  \frac{ - 2 \sin(x) }{1 +  \cos(x) }

will give you an explanation if you want tag me on comment.

4 0
2 years ago
Can someone please help me with this last one. I am totally lost and don’t understand
Ad libitum [116K]

Answer:

g(-4) = -1

g(-1) = -1

g(1) = 3

Explanation:

If you are given a function that is defined by a system of equations associated with certain intervals of x, just find which interval makes x true, and then substitute x into the equation of that interval.

For example, given g(-4), this is an expression which is asking for the value of the equation when x = -4. So -4 is not ≥ 2, so ¼x - 1 will not be used. -4 is also not ≤ -1 and ≤ 2, so -(x - 1)² + 3 will not be used either. So in turn, we will just use -1 which is always -1 so g(-4) will just be -1, right because there is no x variable in -1 so it will always be the same.

Using the same idea as before g(-1) is g(x) when x = -1 so -1 will not be a solution because -1 is not less than -1 (< -1). -1 is not ≥ 2 either so we will be using the second equation because -1 is part of the interval -1≤x≤2 (it is a solution to this inequality), therefore -(x - 1)² + 3 will be used.

As x = -1, -(x - 1)² + 3 = -(-1 - 1)² + 3 = -(-2)² + 3 = -4 + 3 = -1.

It is a coincidence that g(-1) = -1.

Now for g(1), where g(x) has an input of 1 or the value of the function where x = 1, we will not use the first equation because x = 1 → x < -1 → 1 < -1 [this is false because 1 is never less than -1], so we will not use -1.

We will use -(x - 1)² + 3 again because 1 is not ≥ 2, 1≥2 [this is also false]. And -1 ≤ 1 < 2 [This is a true statement]. Therefore g(1) = -(1 - 1)² + 3 = -(0)² + 3 = 3

4 0
3 years ago
A = bh/2 solve for b
rjkz [21]
A =  \dfrac{bh}{2}

Cross multiply:
2A = bh

Divide by h on both sides:
b =  \dfrac{2A}{h}
8 0
3 years ago
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