Answer:
g - 16 is the answer
Step-by-step explanation:
−2 (3g−8g+8) − 9g
Distribute:
= (−2) (3g) + (−2) (−8g) + (−2) (8) + −9g
= −6g + 16g + −16 + − 9g
Combine Like Terms:
=−6g + 16g+ −16+ −9g
= (−6g+16g+−9g) + (−16)
=g+−16
Answer:
=g−16
6 1/4 :) Is this correct?
Answer:
I also need help on this PLZ help
The standard form is 3x+4y=8
<span><span>y = 2 + 2sec(2x)
The upper part of the range will be when the secant has the smallest
positive value up to infinity.
The smallest positive value of the secant is 1
So the minimum of the upper part of the range of
y = 2 + 2sec(2x) is 2 + 2(1) = 2 + 2 = 4
So the upper part of the range is [4, )
The lower part of the range will be from negative infinity
up to when the secant has the largest negative value.
The largest negative value of the secant is -1
So the maximum of the lower part of the range of
y = 2 + 2sec(2x) is 2 + 2(-1) = 2 - 2 = 0
So the lower part of the range is (, 0].
Therefore the range is (, 0] U [4, )
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