$x^2+3x-5=0\\\\a=1;\ b=3;\ c=-5\\\\b^2-4ac=3^2-4\cdot1\cdot(-5)=9+20=29\\\\x_1=\dfrac{-b-\sqrt{b^2-4ac}}{2a};\ x_2=\dfrac{-b+\sqrt{b^2-4ac}}{2a}\\\\x_1=\dfrac{-3-\sqrt{29}}{2\cdot1}=\dfrac{-3-\sqrt{29}}{2}\approx-4.19\\\\x_2=\dfrac{-3+\sqrt{29}}{2\cdot1}=\dfrac{-3+\sqrt{29}}{2}\approx1.19$

5 0

3 years ago

Hi please help fast.!

katovenus [111]

Answer:

sorry I'm not that good with math sorry if I waisted your time ^_^

4 0

2 years ago

Gretchen is setting up for a banquet. She had 300 chairs and needs to distribute them evenly among t tables. (in algebra)

Kazeer [188]

Answer:

The expression is 300/t, , or 300 divided by t

Step-by-step explanation:

3 0

2 years ago