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mr_godi [17]
3 years ago
13

What value is equivilant to 13 - 2(1 - 15)÷4 ​

Mathematics
1 answer:
lesantik [10]3 years ago
3 0

Answer:

20

Step-by-step explanation:

PEMDAS!!!

13 - 2(-14) ÷ 4

13 - [(-28) ÷ 4]

13 - (-7)

13 + 7 = 20

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Javier volunteers in community events each month. He does not do more than five events in a month. He attends exactly five event
enot [183]

Answer:

P(x < 3) = 25\%

E(x) = 3

Step-by-step explanation:

The given parameters can be represented as:

\begin{array}{ccccccc}x & {5} & {4} & {3} & {2} & {1}& {0} & P(x) & {25\%} & {30\%} & {20\%} & {15\%} & {5\%} & {5\%} \ \end{array}

Solving (a): P(x < 3)

This is calculated as:

P(x < 3) = P(x = 0) + P(x = 1) + P(x =2) ----- i.e. all probabilities less than 3

So, we have:

P(x < 3) = 5\% + 5\% + 15\%

P(x < 3) = 25\%

Solving (b): Expected number of events

This is calculated as:

E(x) = \sum x * P(x)

So, we have:

E(x) = 5 * 25\% + 4 * 30\% + 3 * 20\% + 2 * 15\% + 1 * 5\% + 0 * 5\%

E(x) = 125\% + 120\% + 60\% + 30\% + 5\% + 0\%

E(x) = 340\%

Express as decimal

E(x) = 3.40

Approximate to the nearest integer

E(x) = 3

3 0
3 years ago
Question Help A television programmer is arranging the order that five movies will be seen between the hours of 6 P.M. and 4 A.M
Mamont248 [21]
<span>During the indicated time block of 6 PM-4 AM, the movies should go as follows: Since the G rating movies needs to be shown during the first time block, it would be first at 6 pm until around 8 pm. The NC-17 movie would also need to be LAST and from 2 am to 4 am. That leaves 3 movies left to be shown from around 8 pm to 2 Am, which could be shown in 6 different ways. If we assigned EACH movie a title of A, B or C, you get these different showing possibilities- ABC, ACB, BAC, BCA, CAB, and CBA. Since the first and last movies never change, they would default to the first and last positions while the rest is filled in.</span>
6 0
3 years ago
Factor x^3 -4x^2 -3x +18 =0
earnstyle [38]

Answer:

none of the above

Step-by-step explanation:

A graphing calculator shows the zeros to be x=-2, and a double zero at x=3. Hence the factorization is ...

(x +2)(x -3)^2 = 0

The premise that 4 is a zero is incorrect, and none of the answer choices include (x+2) as a factor. The problem is unworkable as written here.

3 0
4 years ago
Free question
jarptica [38.1K]

Answer:

3/4 I think its that

Step-by-step explanation:

its a guess

5 0
3 years ago
How do I do: Subtract w+4 from 6w +3
sammy [17]
I think it should be 5w+7. I'm not 100% sure though
4 0
3 years ago
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