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ipn [44]
3 years ago
7

I don’t know the answer

Mathematics
2 answers:
liberstina [14]3 years ago
5 0

Answer: B

Step-by-step explanation:

taurus [48]3 years ago
3 0

Answer:

b

Step-by-step explanation:

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If an object is dropped from a height of 55 feet, the function d = -16^2 + 55 gives the height of the object after t seconds. Gr
motikmotik

Answer:

Approximately  1.9 seconds   (correct to nearest tenth)

Step-by-step explanation:

Looks like the function is  d = -16t^2 + 55    ( you left out the t)

The answer is the value of t when d = 0 so we have the equation:-

0 =  -16t^2 + 55

16t^2 = 55

t^2 = 55/16

t = sqrt (55/16)

= 1.85 seconds

4 0
3 years ago
Read 2 more answers
1/3 times what equals 1?
Mama L [17]

Answer:

3

Step-by-step explanation:

1/3 + 1/3 + 1/3 = 3/3 = 1 whole.

1/3 x 3 = 1

Hope this helps!

5 0
2 years ago
Find (fºg)(1)<br> f(x) = x² - 1<br> g(x) = √x <br> A.0<br> B.1<br> C.4 √2<br> D. √8
Savatey [412]

Given:

The function are

f(x)=x^2-1

g(x)=\sqrt{x}

To find:

The value of (f\circ g)(1).

Solution:

We have,

f(x)=x^2-1

g(x)=\sqrt{x}

We need to find the value of (f\circ g)(1).

(f\circ g)(1)=f(g(1))            [\because (f\circ g)(x)=f(g(x))]

(f\circ g)(1)=f(\sqrt{1})            [\because g(x)=\sqrt{x}]

(f\circ g)(1)=f(1)      

(f\circ g)(1)=(1)^2-1                  [\because f(x)=x^2-1]

(f\circ g)(1)=1-1      

(f\circ g)(1)=0      

The value of (f\circ g)(1) is 0.

Therefore, the correct option is A.

4 0
3 years ago
Need help as fast as possible will mark brainliest
MissTica

Answer:

Option C. is correct choice.

Step-by-step explanation:

20\pm 0.1\:^{\circ}\:C

Regards: Umer

6 0
3 years ago
X5+12x3-5x÷2x6+4x3+x2-2​
TEA [102]
22 I think If I worked it out right
7 0
3 years ago
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