Answer:
99% confidence interval for the soil water content is determined by
(0.19474, 0.26926)
Step-by-step explanation:
<u><em>Explanation</em></u>:-
Given mean of the sample = 23.2% = 0.232
Given standard deviation of the sample = 1.0% =0.01
Given sample size 'n' =4
Degrees of freedom = n-1 =4-1 =3
critical value = 0.01
99% confidence interval for the soil water content is determined by


( 0.232 -0.03726 , 0.232 +0.03726)
(0.19474, 0.26926)
<u><em>Final answer:</em></u>-
99% confidence interval for the soil water content is determined by
(0.19474, 0.26926)