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2 years ago

On a number line, why is 0 important?

2 answers:

4 0

0 is the starting pointing for equations that are for positive numbers. 0 sets an easy way to figure out problems that have negatives. 0 is important to solve any problem with integers, and decimals!

Amanda [17]2 years ago

3 0

0 is important because it is the start of the number with no 0 how will u beginning it

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35/k = 7/3 what is this answer

miv72 [106K]

Answer:

K=15

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

Integers are also known as....

Arada [10]

In short, the set formed by the negative integers, the number zero and the positive integers (or natural numbers) is called the set of integers. Integer is also known as a whole number.

5 0

2 years ago

1.(03.03 MC) The table below represents a linear function f(x) and the equation represents a function g(x).

Mama L [17]

The slope of f(x) is 10 and the slope of g(x) is 5; g(x) has the greater y-intercept.

To find the slope of f(x), we use the slope formula: m=(y₂-y₁)/(x₂-x₁) = (-1--11)/(0--1) = (-1+11)/(0+1) = 10/1 = 10.

To find the slope of g(x), we just look at the form it is in. It is written in slope-intercept form, y=mx+b, where m is the slope. The number in g(x) that would correspond to m is 5.

The y-intercept of f(x) is found by looking at the points. Any y-intercept will have an x-coordinate of 0; the only point like this in the table is (0, -1) so the y-intercept is -1.

For g(x), we again look at the form y=mx+b. The number that corresponds with b is the y-intercept; in this case, it is 1. 1>-1, so g(x) has the larger y-intercept.

7 0

2 years ago

1. S(–4, –4), P(4, –2), A(6, 6) and Z(–2, 4) a) Apply the distance formula for each side to determine whether SPAZ is equilatera

Aleksandr [31]

Answer:

a) SPAZ is equilateral.

b) Diagonals SA and PZ are perpendicular to each other.

c) Diagonals SA and PZ bisect each other.

Step-by-step explanation:

At first we form the triangle with the help of a graphing tool and whose result is attached below. It seems to be a paralellogram.

a) If figure is equilateral, then SP = PA = AZ = ZS:

$SP = \sqrt{[4-(-4)]^{2}+[(-2)-(-4)]^{2}}$

$SP \approx 8.246$

$PA = \sqrt{(6-4)^{2}+[6-(-2)]^{2}}$

$PA \approx 8.246$

$AZ =\sqrt{(-2-6)^{2}+(4-6)^{2}}$

$AZ \approx 8.246$

$ZS = \sqrt{[-4-(-2)]^{2}+(-4-4)^{2}}$

$ZS \approx 8.246$

Therefore, SPAZ is equilateral.

b) We use the slope formula to determine the inclination of diagonals SA and PZ:

$m_{SA} = \frac{6-(-4)}{6-(-4)}$

$m_{SA} = 1$

$m_{PZ} = \frac{4-(-2)}{-2-4}$

$m_{PZ} = -1$

Since $m_{SA}\cdot m_{PZ} = -1$ , diagonals SA and PZ are perpendicular to each other.

c) The diagonals bisect each other if and only if both have the same midpoint. Now we proceed to determine the midpoints of each diagonal:

$M_{SA} = \frac{1}{2}\cdot S(x,y) + \frac{1}{2}\cdot A(x,y)$

$M_{SA} = \frac{1}{2}\cdot (-4,-4)+\frac{1}{2}\cdot (6,6)$

$M_{SA} = (-2,-2)+(3,3)$

$M_{SA} = (1,1)$

$M_{PZ} = \frac{1}{2}\cdot P(x,y) + \frac{1}{2}\cdot Z(x,y)$

$M_{PZ} = \frac{1}{2}\cdot (4,-2)+\frac{1}{2}\cdot (-2,4)$

$M_{PZ} = (2,-1)+(-1,2)$

$M_{PZ} = (1,1)$

Then, the diagonals SA and PZ bisect each other.

8 0

2 years ago

Suppose that the price p, in dollars, and the number of sales, x, of a certain item follow the equation 5p+5x+3px=71. Suppose al

vova2212 [387]

Answer:

decrease of 1.153 sales per day

Step-by-step explanation:

Given:-

- The price of item = p

- The number of sales = x

- The relationship between "p" and "x" is given below:

5p+5x+3px=71

Find:-

Find the rate at which x is changing when x=3, p=4, and dp/dt=1.4. The rate at which x is changing is [ ] sales per day

Solution:-

- Take the time derivative (d/dt) of the entire given expression and apply chain rule on d/dt ( 3px ). Since both "p" and "x" are only functions of time "t":

d/dt (5p+5x+3px=71)

5*dp/dt + 5*dx/dt + 3* ( x*dp/dt + p*dx/dt) = 0

- Use the given values x=3, p=4, and dp/dt=1.4 to determine dx/dt:

5*1.4 + 5*dx/dt + 3*3*1.4 + 3*4*dx/dt = 0

17dx/dt = -19.6

dx/dt = -1.153 sales per day

- There is a decrease of 1.153 sales per day.

6 0

2 years ago