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enyata [817]
3 years ago
9

Teresa is maintaining a campfire. she has kept the fire steadily burning 4 hours with 6 logs. She wants to know how many logs sh

e need to keep the fire burning for 18 hours. Select the equations tessa can use, and determine the number of logs she needs to maintain the fire for 18 hours. Select all that apply.
A. X/6=4/18
B. X/6=18/4
C. X/18=6/4
D. X/4=18/6
E. 4/6=18/X
Mathematics
2 answers:
erica [24]3 years ago
5 0
  • D. X/4=18/6

Step-by-step explanation:

Let x be the number of logs=18 hours

6 logs=4 hours

X*4=18*6

4x=108

x=27 logs

so therefore 27 logs are needed to keep the fire burning for 18 hours

umka21 [38]3 years ago
5 0
The believe the answer is D
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Lines k and n intersect on the y-axis
avanturin [10]

a) The equation of line k is:

y = -\frac{202}{167}x + \frac{598}{167}

b) The equation of line j is:

y = \frac{167}{202}x + \frac{1546}{202}

The equation of a line, in <u>slope-intercept formula</u>, is given by:

y = mx + b

In which:

  • m is the slope, which is the rate of change.
  • b is the y-intercept, which is the value of y when x = 0.

Item a:

  • Line k intersects line m with an angle of 109º, thus:

\tan{109^{\circ}} = \frac{m_2 - m_1}{1 + m_1m_2}

In which m_1 and m_2 are the slopes of <u>k and m.</u>

  • Line k goes through points (-3,-1) and (5,2), thus, it's slope is:

m_1 = \frac{2 - (-1)}{5 - (-3)} = \frac{3}{8}

  • The tangent of 109 degrees is \tan{109^{\circ}} = -\frac{29}{10}
  • Thus, the slope of line m is found solving the following equation:

\tan{109^{\circ}} = \frac{m_2 - m_1}{1 + m_1m_2}

-\frac{29}{10} = \frac{m_2 - \frac{3}{8}}{1 + \frac{3}{8}m_2}

m_2 - \frac{3}{8} = -\frac{29}{10} - \frac{87}{80}m_2

m_2 + \frac{87}{80}m_2 = -\frac{29}{10} + \frac{3}{8}

\frac{167m_2}{80} = \frac{-202}{80}

m_2 = -\frac{202}{167}

Thus:

y = -\frac{202}{167}x + b

It goes through point (-2,6), that is, when x = -2, y = 6, and this is used to find b.

y = -\frac{202}{167}x + b

6 = -\frac{202}{167}(-2) + b

b = 6 - \frac{404}{167}

b = \frac{6(167)-404}{167}

b = \frac{598}{167}

Thus. the equation of line k, in slope-intercept formula, is:

y = -\frac{202}{167}x + \frac{598}{167}

Item b:

  • Lines j and k intersect at an angle of 90º, thus they are perpendicular, which means that the multiplication of their slopes is -1.

Thus, the slope of line j is:

-\frac{202}{167}m = -1

m = \frac{167}{202}

Then

y = \frac{167}{202}x + b

Also goes through point (-2,6), thus:

6 = \frac{167}{202}(-2) + b

b = \frac{(2)167 + 202(6)}{202}

b = \frac{1546}{202}

The equation of line j is:

y = \frac{167}{202}x + \frac{1546}{202}

A similar problem is given at brainly.com/question/16302622

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jake went on a road trip with his family this summer. On Monday, they drove 629 miles. Tuesday, they drove 215 miles. On Wednesd
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Jake’s family traveled a total of 1,543 miles
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Pavlova-9 [17]
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Answer:

For every pound that the package weight increases, the price of sending it increases by $3.80.

Step-by-step explanation:

The coefficient 3.80 multiplies the variable x (package weight), so if x is 1 pound the cost increase $3.80, if x is 2 pound the cost increase 2*3.80 = $7.6, and so on.  Generally speaking, for every pound that the package weight increases the cost increases by $3.80.

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Nikolay [14]

Answer:

125 g

Step-by-step explanation:

mg is so little for an orange and kg is too large

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