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enyata [817]
3 years ago
9

Teresa is maintaining a campfire. she has kept the fire steadily burning 4 hours with 6 logs. She wants to know how many logs sh

e need to keep the fire burning for 18 hours. Select the equations tessa can use, and determine the number of logs she needs to maintain the fire for 18 hours. Select all that apply.
A. X/6=4/18
B. X/6=18/4
C. X/18=6/4
D. X/4=18/6
E. 4/6=18/X
Mathematics
2 answers:
erica [24]3 years ago
5 0
  • D. X/4=18/6

Step-by-step explanation:

Let x be the number of logs=18 hours

6 logs=4 hours

X*4=18*6

4x=108

x=27 logs

so therefore 27 logs are needed to keep the fire burning for 18 hours

umka21 [38]3 years ago
5 0
The believe the answer is D
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Paul owns a mobile wood-fired pizza oven operation. A couple of his clients complained about his dough at a recent catering, so
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Answer: B. Do not reject H0, we cannot conclude the proportion of customer complaints is more for the old dough

Step-by-step explanation:

This is a test of 2 population proportions. Let 1 and 2 be the subscript for the old and the new dough players. The population proportions of customer complaints with the old and new dough would be p1 and p2

P1 - P2 = difference in the proportion of customer complaints with the old and new dough.

The null hypothesis is

H0 : p1 ≥ p2

pm - pw ≥ 0

The alternative hypothesis is

Ha : p1 < p2

p1 - p2 < 0

it is a left tailed test

Sample proportion = x/n

Where

x represents number of success(number of complaints)

n represents number of samples

For old dough

x1 = 6

n1 = 385

P1 = 6/385 = 0.016

For new dough,

x2 = 16

n2 = 340

P2 = 16/340 = 0.047

The pooled proportion, pc is

pc = (x1 + x2)/(n1 + n2)

pc = (6 + 16)/(385 + 340) = 0.03

1 - pc = 1 - 0.03 = 0.97

z = (Pm - Pw)/√pc(1 - pc)(1/nm + 1/nw)

z = (0.016 - 0.047)/√(0.03)(0.97)(1/385 + 1/340) = - 0.031/√0.00553857907

z = - 0.42

Since it is a left tailed test, we would find the p value for the area to the left of the z score. From the normal distribution table,

p value = 0.337

For a 95% confidence level, the significant level, alpha is

1 - 0.95 = 0.05

Since 0.05 < 0.337, we would accept the null hypothesis

Therefore, Do not reject H0, we cannot conclude the proportion of customer complaints is more for the old dough

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