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Mnenie [13.5K]
2 years ago
6

In the coordinate plane , the points (-3,2) and (7,-2) are the endpoints of a diameter of a circle. what are the coordinates of

the center circle
Mathematics
1 answer:
AVprozaik [17]2 years ago
8 0
The centre of the circle will be the midpoint of the two coordinates

\text {Midpoint = }  \bigg( \dfrac{X_1 + X_2}{2} , \dfrac{Y_1 + Y_2}{2} \bigg)

\text {Midpoint = }  \bigg( \dfrac{-3 + 7}{2} , \dfrac{2+ (-2)}{2} \bigg)

\text {Midpoint = }  \bigg( \dfrac{4}{2} , \dfrac{0}{2} \bigg)

\text {Midpoint = }  \bigg( 2, 0 \bigg)

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Answer: Coordinate of the centre of the circle = (2, 0)
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Answer: y = -2x - 7

Step-by-step explanation:

The equation for a perpenducular line has a slope that is the negative inverse of the reference line, in this case x - 2y = 6.

Let's put this equation into standard slope-intercept form, y = mx+b, where m is the slope and b the y-intercept (the value of y when x is 0).

x - 2y = 6

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The slope is (1/2), so a perpendicular line will have a slope of -2.

y = -2x + b

We can find b by using the given point ((-3,-1), a known solution):

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Equation is <span>-4x+6y-5z=60
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Step-by-step explanation:

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