All categories

2 years ago

Use a definition, postulate, or theorem to find the value of x in the figure described.

Mathematics

1 answer:

Rudiy272 years ago

6 0

we know that

An <u>angle bisector</u> is a line or ray that divides an angle into two congruent angles

in this problem

m∠RST=m∠RSV+m∠VST

m∠RSV=m∠VST

hence

m∠RST=2*m∠RSV --------> equation 1

we have

m∠RST=(6x-24)

m∠RSV=(2x+8)

Substitute in the equation 1

6x-24=2*(2x+8)

6x-24=4x+16

6x-4x=16+24

2x=40

x=40/2

x=20 degrees

therefore

<u>the answer is the option </u>

D definition of angle bisector

and the value of x is 20 degrees

You might be interested in

41 kilometers to meter

g100num [7]

Answer:

41000 meters

Step-by-step explanation:

multiply the length value by 1000

4 0

3 years ago

Read 2 more answers

Please help. I’ll mark you as brainliest if correct!

chubhunter [2.5K]

Answer:

$\boxed{\sf \ \ \ f^{-1}(x)=1+\sqrt{x} \ \ \ }$

Step-by-step explanation:

the minimum of f is for x = 1 and f(1)=0

f is decreasing for x<=1 and increasing for x>=1

so the domain is $[1;+\infty[$

$f^{-1}(f(x))=x =f^{-1}((x-1)^2)\\\\f(f^{-1}(x))=x=(f^{-1}(x)-1)^2$

x>=1 so x is positive and we can take the square root

so $f^{-1}(x)=1+\sqrt{x}$

8 0

2 years ago

Given a line segment that contains the points A,B, & C in order, if AB = x, BC = x, and AC is equal to 36, then x = _____.

Bumek [7]

Answer:

a. 18

Step-by-step explanation:

AB+BC = AC

x + x = 36

2x = 36

x = 36/2

x = 18

6 0

2 years ago

The parabola y=<img src="https://tex.z-dn.net/?f=x%5E%7B2%7D" id="TexFormula1" title="x^{2}" alt="x^{2}" align="absmiddle" class

oksano4ka [1.4K]

Y=(x-h)^2+k where (h,k) is the vertex

So, equation of new parabola is:

y=(x+1)^2+7

7 0

2 years ago

Identify the vertex of the quadratic function in standard form y=2x^2 -16x+31

lapo4ka [179]

Answer:

(4,1)

Step-by-step explanation:

The vertex of the quadratic can be found using -b/2a. The vertex is the point (-b/2a, f(-b/2a)).

To find the x coordinate of the quadratic, define its a,b, and c. The quadratic has a = 2, b=-16, and c=31. Then -b/2a is -(-16)/2(2) = 16/4 = 4.

To find the y-coordinate, input the x=4 and solve for y.

$y=2(4)^2-16(4)+31\\y=2(16)-64+31\\y=32-64+31\\y=1$

The vertex is (4,1).

8 0

3 years ago