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2 years ago

QUICK QUESTION! PLEASE HELP ME

Mathematics

2 answers:

melomori [17]2 years ago

6 0

Y = x/3 because I searched it up

hoa [83]2 years ago

4 0

Answer:

y=3/x

Step-by-step explanation:

You might be interested in

A triangular pyramid has a base with an area of 43 cm squared and lateral faces with bases of 10 cm and heights of 8.6 cm. What

Jet001 [13]

Answer:

The total surface area of triangular pyramid is 172 cm squared

Step-by-step explanation:

Triangular pyramid:

Number of faces 4.
Number of vertices of a triangular pyramid is 6.
The volume is $\frac13 AH$ . A= area of the pyramid's base and H= height of the pyramid.

The surface area of triangular pyramid B+L. B= area of base, L= area of lateral surface.

Given that, the area of the base is 43 cm squared. Lateral faces with bases of 10 cm and heights 8.6 cm.

The 3 sides of the triangular pyramid is triangle in shape.

The area of triangle is $\frac12 \times base \times height$ .

The lateral surface area of the triangular pyramid is

$=3(\frac12 \times base \times height)$

$=3(\frac12\times 10\times8.6)$ cm squared

=129 cm squared

The total surface area of triangular pyramid is

=Area of the base + lateral surface area

=(43+129) cm squared

=172 cm squared

8 0

3 years ago

What is the value of x?<br><br> x−16=8

FinnZ [79.3K]

Answer:

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

Look at the photo and put your answer down.

Margarita [4]

No solution, I hope I helped (:

8 0

3 years ago

Read 2 more answers

What is 20/10 as a whole number

iren2701 [21]

20/10 is same as 20:10 so the whole number is 2

4 0

2 years ago

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A bag contains five white balls and five black balls. Your goal is to draw two black balls.

umka21 [38]

Answer:

a.) the probability that both the ball drawn are black = $\frac{10}{45} = \frac{2}{9}$

b.) Sum of all the probabilities = $\frac{\frac{2}{9} }{1 - \frac{2}{9} } = \frac{\frac{2}{9} }{\frac{8}{9} } = \frac{2}{8} =\frac{1}{4} = 0.25$

Step-by-step explanation:

a) two balls are drawn at random .

total number of balls = 10

number of black balls = 5

number of white balls = 5.

the number of ways two balls can be drawn = $\binom{10}{2} = \frac{10!}{2! 8!} = \frac{10\times9}{2} = 45$

the number of ways two black balls can be drawn = $\binom{5}{2} = \frac{5!}{2! 3!} = \frac{5\times4}{2} = 10$

the probability that both the ball drawn are black = $\frac{10}{45} = \frac{2}{9}$

b) probability that First draw of two black balls = $\frac{2}{9}$

probability that first draw is of two white balls is and second draw is of

two black balls = $\frac{2}{9} \times\frac{2}{9}$

Probability that first two draws are of white balls and the third draw is of

two black balls = $\frac{2}{9} \times\frac{2}{9} \times\frac{2}{9}$

This is a geometric sequence and the final probability will be the sum of

all such probabilities, where we can take the the sequence to be an infinite series and the first term is $\frac{2}{9}$ and the common ratio is $\frac{2}{9}$ which is less than 1.

Sum of all the probabilities = $\frac{\frac{2}{9} }{1 - \frac{2}{9} } = \frac{\frac{2}{9} }{\frac{8}{9} } = \frac{2}{8} =\frac{1}{4} = 0.25$

3 0

3 years ago