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2 years ago

Help me please i don’t get how to point slope this equation please

Mathematics

1 answer:

PSYCHO15rus [73]2 years ago

3 0

Answer:

y-5=3x-15

Step-by-step explanation:

Slope=(5+1)/(-6+8)

=6/2

Equation of line passing throgh point (-6,5):

y-5=3(x-5)

y-5=3x-15

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Two high schools are going on a field trip. One rents 8 vans and 9 buses for 228 students. The other rents 4 vans and 5 buses fo

nevsk [136]

Answer:

No. pp you can fit in a van: 6,

No. pp you can fit in a bus: 20

Step-by-step explanation:

Let v = # of pp in vans, and let b = # of pp in buses:

8v + 9b = 228,

4v + 5b = 124

If we solve this system of equations by substitution, we isolate the first eq. for v and then substitute into the bottom eq:

v = 228-9b/8,

Substitute v = 228-9b/8 into bottom eq:

[4 * 228-9b/8 + 5b = 125]

[228+b/2=124]

[228+b = 248]

[b = 20]

Now substitute 20 to find no. of pp in the vans:

v = 228 - 9(20)/8 = 228 - 180/8 = 48/8 = 6

8 0

2 years ago

What is the volume of the following rectangle prism? Plz help

Advocard [28]

Answer:

7 2/3 or 7.666

Step-by-step explanation:

To find the volume of a rectangular prism, multiply its 3 dimensions: length x width x height. The volume is expressed in cubic units.

since we only have two points we have to do

4/3 x 23/4 = 7 2/3 or 7.666

so the answer is 7 2/3 or 7.666

6 0

2 years ago

What is the value of the expression i 0 × i 1 × i 2 × i 3 × i 4?

astraxan [27]

ANSWER

The value of the expression is
$- 1$

EXPLANATION

Method 1: Rewrite as product of
${i}^{2}$

The expression given to us is,

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4}$

We use the fact that
${i}^{2} = - 1$
to simplify the above expression.

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4} = {i}^{0} \times {i}^{1} \times {i}^{3} \times {i}^{2} \times {i}^{4}$

This implies,

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4} = {i}^{0} \times {i}^{2} \times {i}^{2} \times {i}^{2} \times {i}^{2} \times {i}^{2}$

We substitute to obtain,

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4} = 1\times - 1 \times - 1 \times - 1\times - 1 \times - 1$

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4} = 1\times 1 \times 1 \times - 1 = - 1$

Method 2: Use indices to solve.

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4} = {i}^{0 + 1 + 2 + 3 + 4}$

This implies that,

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4} = {i}^{10}$

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4} = ( {{i}^{2}} )^{5}$

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4} = ( - 1 )^{5} = - 1$

8 0

3 years ago

Read 2 more answers

Given h(x) = 4x2 - 5x + 4 find h(-5).

MrRissso [65]

9514 1404 393

Answer:

h(-5) = 129

Step-by-step explanation:

Put -5 where x is and do the arithmetic.

h(-5) = 4(-5)² -5(-5) +4

h(-5) = 4(25) +25 +4 = 129