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3 years ago

3. Find the slope between the two points (-3,3) and (3,-1) Your Answer:

Mathematics

2 answers:

liberstina [14]3 years ago

8 0

I’ve attached my work..
I did two different methods to do this visually and mathematical
Hope this helps!

WARRIOR [948]3 years ago

4 0

The slope is -2/3 I hope this helped

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Answer:

4 and 7

Step-by-step explanation:

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Need help with Calculus 1 inverse trig functions

lidiya [134]

Answer:

$\displaystyle y'=3\frac{1+\frac{x}{\sqrt{1+x^2}}}{2+2x^2+2x\sqrt{1+x^2}}$

Step-by-step explanation:

<u>The Derivative of a Function</u>

The derivative of f, also known as the instantaneous rate of change, or the slope of the tangent line to the graph of f, can be computed by the definition formula

$\displaystyle f'(x)=\lim\limits_{\Delta x \rightarrow 0}\frac{f(x+\Delta x)-f(x)}{\Delta x}$

There are tables where the derivative of all known functions are provided for an easy calculation of specific functions.

The derivative of the inverse tangent is given as

$\displaystyle (tan^{-1}u)'=\frac{u'}{1+u^2}$

Where u is a function of x as provided:

$y=3tan^{-1}(x+\sqrt{1+x^2})$

If we set

$u=(x+\sqrt{1+x^2})$

Then

$\displaystyle u'=1+\frac{2x}{2\sqrt{1+x^2}}$

$\displaystyle u'=1+\frac{x}{\sqrt{1+x^2}}$

Taking the derivative of y

$y'=3[tan^{-1}(x+\sqrt{1+x^2})]'$

Using the change of variables

$\displaystyle y'=3[tan^{-1}u]'=3\frac{u'}{1+u^2}$

$\displaystyle y'=3\frac{u'}{1+u^2}=3\frac{1+\frac{x}{\sqrt{1+x^2}}}{1+(x+\sqrt{1+x^2})^2}$

Operating

$\displaystyle y'=3\frac{1+\frac{x}{\sqrt{1+x^2}}}{1+x^2+2x\sqrt{1+x^2}+1+x^2}$

$\boxed{\displaystyle y'=3\frac{1+\frac{x}{\sqrt{1+x^2}}}{2+2x^2+2x\sqrt{1+x^2}}}$

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3 years ago

Which expression is equivalent to 8(k + m) - 15(2k + 5m)?<br> agul

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Answer:

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Step-by-step explanation:

You have to use the Distributive property:

8(k + m) - 15 (2k + 5m)

8k + 8m - 30k - 75m

Now simplify:

8k - 30k + 8m - 75m

-22k - 67m

Be careful with positives and negatives!

Hope this help!

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3 years ago

Identify the distance between points (−3,−6,7) and (−9,5,−4), and identify the midpoint of the segment for which these are the e

melisa1 [442]

Step-by-step explanation:

LET THE Point 1 A and point 2 is B

(AB) ^2=(-9-(-3))^2+ (5-(-6))^2+(-4-7)^2=278

AB=16.67 length unit

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X=-9-3/2 =-6

Y=5-6/2=-0.5

Z=-4+7/2=-1.5

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3. Find the slope between the two points (-3,3) and (3,-1) Your Answer:​

3. Find the slope between the two points (-3,3) and (3,-1) Your Answer: