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2 years ago

What is the least common mutliple of 10 and 12?

Mathematics

2 answers:

harkovskaia [24]2 years ago

7 0

Hey there!

10: 10, 20, 30, 40, 50, 60, and etc.

12: 12, 24, 36, 48, 60, 72, 84, 96, 108, 120, 132, 144

Lowest Common Multiple (LCM) of BOTH of your given NUMBERS, is most likely: 60 ✅

Answer: 60 ☑️

Good luck on your assignment and enjoy your day!

~Amphitrite1040:)

GalinKa [24]2 years ago

3 0

Answer:

Step-by-step explanation:

You can divide both of them by 2

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Any help would be appreciated. Thank you!

trapecia [35]

Answer:

Area $=62.5\sqrt{6}$ square units

$AB=5\sqrt{15}$ units

$BC=5\sqrt{10}$ units

Step-by-step explanation:

In a right triangle the altitude drawn to the hypotenuse is the geometric mean of the segments at which this altitude divides the hypotenuse.

So,

$BD^2=15\cdot 10\\ \\BD^2=150\\ \\BD=\sqrt{150}=5\sqrt{6}\ units$

a. The area of the triangle ABC is

$A_{ABC}=\dfrac{1}{2}\cdot BD\cdot AC=\dfrac{1}{2}\cdot 5\sqrt{6}\cdot (15+10)=\dfrac{125\sqrt{6}}{2}=62.5\sqrt{6}\ un^2.$

b. The legs of the right triangle are geometric means of the segment adjacent to this leg and the hypotenuse, so

$AB^2=AD\cdot AC=15\cdot 25\Rightarrow AB=5\sqrt{15}\ units\\ \\BC^2=CD\cdot AC=10\cdot 25\Rightarrow BC=5\sqrt{10}\ units$

5 0

3 years ago

How to find restrictions on x

katrin [286]

Can you please explain more? I don’t get what you mean.....

4 0

2 years ago

I need help with this question? 2(t+1) =10

ANEK [815]

Answer:

Distribute

Subtract two from both sides of the equation

Simplify

and that's your solution

which should be t=4

Step-by-step explanation:

3 0

2 years ago

Find the Fourier series of f on the given interval. f(x) = 1, ?7 < x < 0 1 + x, 0 ? x < 7

Zolol [24]

$f(x)=\begin{cases}1&\text{for }-7$

The Fourier series expansion of $f(x)$ is given by

$\dfrac{a_0}2+\displaystyle\sum_{n\ge1}a_n\cos\frac{n\pi x}7+\sum_{n\ge1}b_n\sin\frac{n\pi x}7$

where we have

$a_0=\displaystyle\frac17\int_{-7}^7f(x)\,\mathrm dx$
$a_0=\displaystyle\frac17\left(\int_{-7}^0\mathrm dx+\int_0^7(1+x)\,\mathrm dx\right)$
$a_0=\dfrac{7+\frac{63}2}7=\dfrac{11}2$

The coefficients of the cosine series are

$a_n=\displaystyle\frac17\int_{-7}^7f(x)\cos\dfrac{n\pi x}7\,\mathrm dx$
$a_n=\displaystyle\frac17\left(\int_{-7}^0\cos\frac{n\pi x}7\,\mathrm dx+\int_0^7(1+x)\cos\frac{n\pi x}7\,\mathrm dx\right)$
$a_n=\dfrac{9\sin n\pi}{n\pi}+\dfrac{7\cos n\pi-7}{n^2\pi^2}$
$a_n=\dfrac{7(-1)^n-7}{n^2\pi^2}$

When $n$ is even, the numerator vanishes, so we consider odd $n$ , i.e. $n=2k-1$ for $k\in\mathbb N$ , leaving us with

$a_n=a_{2k-1}=\dfrac{7(-1)-7}{(2k-1)^2\pi^2}=-\dfrac{14}{(2k-1)^2\pi^2}$

Meanwhile, the coefficients of the sine series are given by

$b_n=\displaystyle\frac17\int_{-7}^7f(x)\sin\dfrac{n\pi x}7\,\mathrm dx$
$b_n=\displaystyle\frac17\left(\int_{-7}^0\sin\dfrac{n\pi x}7\,\mathrm dx+\int_0^7(1+x)\sin\dfrac{n\pi x}7\,\mathrm dx\right)$
$b_n=-\dfrac{7\cos n\pi}{n\pi}+\dfrac{7\sin n\pi}{n^2\pi^2}$
$b_n=\dfrac{7(-1)^{n+1}}{n\pi}$

So the Fourier series expansion for $f(x)$ is

$f(x)\sim\dfrac{11}4-\dfrac{14}{\pi^2}\displaystyle\sum_{n\ge1}\frac1{(2n-1)^2}\cos\frac{(2n-1)\pi x}7+\frac7\pi\sum_{n\ge1}\frac{(-1)^{n+1}}n\sin\frac{n\pi x}7$

3 0

2 years ago

Which expression has twice the value of 2 times 2 times 2 times 2 times 2?

Brilliant_brown [7]

Answer:

2 To the 6'th power.

Step-by-step explanation:

2x2x2x2x2=32

twice the value of 32 is 64

2x2x2x2x2x2=64

so your answer would be 2 to the sixth power

hope this helps! :)

3 0

3 years ago

Read 2 more answers