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DENIUS [597]
3 years ago
13

Can someone help me out with this question?

Mathematics
1 answer:
goblinko [34]3 years ago
6 0

Answer:

The third option

Step-by-step explanation:

The third option represents 65 over 100, meaning 65% of whatever of it would the 65% of 90 be

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To eliminate 6X you would Transform 2x by multiplying what number ?
NARA [144]

Answer:

-3

Step-by-step explanation:

to eliminate 6x we need the same no. 6x but that should be negative. so

2X × -3 = -6X

and

6X+(-6X)=0

5 0
3 years ago
What is the solution to the inequality -13x+6<14-5x
kvv77 [185]

Answer:

x > -1

Step-by-step explanation:

-13x+6

-13x+5x

-8x

\frac{-8x}{-8} >\frac{8}{-8}

x>-1

* Remember that,

if you have a negative sign (-) infront of the x you have to change the direction of the inequality sign.

Hope this helps you .

Let me know if you have any other questions :-)

7 0
3 years ago
How many ounces of water are equal to 6/8 cups of water
MatroZZZ [7]
US Cups US Fluid Ounces
6 cup US 48.00 us fl oz
7 cup US 56.00 us fl oz
8 cup US 64.00 us fl oz
9 cup US 72.00 us fl oz

1 Cup = 8 Fluid Ounces

7 0
3 years ago
HELP ASAP PLEASEEEEEEEEEE
Andrew [12]

Given the recursive formula, each terms is five time the previous one.

This means that:

  • f(6) is 5 times f(5), which means f(6)=5f(5)
  • in turn, f(5) is 5 times f(4), so we have f(5)=5f(4). This means that f(6)=5f(5)=5\cdot 5f(4) = 25f(4)
  • Finally, f(4)=5f(3) So, substituting this back gives

f(6)=25f(4)=25\cdot 5f(3)=125f(3)

In general, since you have f(n)=5f(n-1), each time you compute a new term you multiply by a factor of 5, so if m=n+k, you have

f(m)=5^kf(n)

4 0
3 years ago
Find the constant rate of change for each linear function and interpret its meaning
Marina CMI [18]

the slope goes by several names

• average rate of change

• rate of change

• deltaY over deltaX

• Δy over Δx

• rise over run

• gradient

• constant of proportionality

however, is the same cat wearing different costumes.

and to get it, we simply need two points off of the straight line, hmm let's use the ones in the picture below.

(\stackrel{x_1}{2}~,~\stackrel{y_1}{4})\qquad (\stackrel{x_2}{6}~,~\stackrel{y_2}{6}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{6}-\stackrel{y1}{4}}}{\underset{run} {\underset{x_2}{6}-\underset{x_1}{2}}}\implies \cfrac{2}{4}\implies \cfrac{1}{2}

3 0
2 years ago
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