Answer:
a
Explanation:
A Dutch auction is a method for pricing shares (often in an initial public offering) whereby the price of the shares offered is lowered until there are enough bids to sell all shares. All the shares are then sold at that price. The goal of a Dutch auction is the find the optimal price at which to sell a security.
For example, let's assume Company XYZ wants to sell 10 million shares using a Dutch auction. To participate in a Dutch auction, an investor typically opens an account with Company XYZ's underwriter (usually an investment bank), obtains a prospectus, and obtains an access code or bidder identification code (Dutch auctions often occur online).
During bidding, investors indicate how many shares they're willing to buy and the price they're willing to pay. The underwriter, who acts as the auctioneer, usually starts the auction by offering a prohibitively high price for the security (say, $40 per share in this case). It then lowers the price gradually to say, $36 per share, where two bids come in for 500,000 shares. The underwriter then lowers the price again, this time to $35, and attracts 4,000,000 shares worth of bids. After lowering the price to $34, the underwriter gets another 5,000,000 shares worth of bids; then the underwriter lowers the price to $33 and gets another 3,000,000 in bids before the auction ends.
Answer:
(a) The cost in dollars of all the main-floor seats that were sold: 42m + 25b. (b) The total number of seats that were sold for the performance: m+b.
Explanation:
Its understood that 1 tickect is equal to 1 seat, therefore the number of seats = number of tickets regardless of the type of seat. With this assumption, the algebraic expressions can be done.
I would say false. the par value is not necessarily the amount that the investor must pay in order to purchase the preferred stock. the par value is known to be the market price of the stock however, investors may offer the stock above or below the par value depending on the decision of the board
It’s C) The geocentric orientation
I hope this helped out, have a nice day! :)
