The sum of negative 5a and 3 is greater than 1.
Since f(x) is a polynomial with 3rd degree, then it will have 3 roots (zeroes)
One of them is real and the other two are complex conjugate roots
Since the real root is 4, then
x = 4
Since the complex root is (1 - i), then
The other root will be the conjugate of it (1 + i)
x = (1 - i)
x = (1 + i)
To find f(x) we will multiply the three factors of it
We can get the factors from the zeroes

Subtract 4 from both sides

The first factor is (x - 4)

The second factor is (x - 1 + i)
The third factor is (x - 1 - i)

We will multiply them to find f(x)

Multiply it by (x - 4)

The answer is
Answer:
It’s not allowing me to place done the work but the answer is 8 sorry!
Answer:
Step-by-step explanation:
First, lets simplify everything in the parenthesis.
(3×10^2 )×(2×10^−4 )=
In the parenthesis, since exponents come before multiplication in the order of operations, we need to do the exponents first.
(3 • 100) • (2 • 1/10^4)
Now, we can just multiply everything from left to right to get:
6*10^-2
Or
.06