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2 years ago

,,,,,,,,,,,,,,,,,,,,,,,,,

Mathematics

1 answer:

jonny [76]2 years ago

8 0

Answer:

side

Step-by-step explanation:

if your talking about the dark purple it would be the side but if your talking about the other one it would be front i cant rlly tell by the colors.

i hope this helps:)

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1.4=0.7p solve the equation

WINSTONCH [101]

You need to isolate p:
1.4 divided by 0.7 = 0.7p divided by 0.7 (this eliminates 0.7)
2 = p

4 0

3 years ago

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Simplify 6m2n3 – 3m3n2 + 8m2n3 + 12m3n2

NISA [10]

Hello! Hope I can assist you.

Let us simplify some terms first!

$6m\cdot \:2n\cdot \:3 \ \textgreater \ 36mn$
$3m\cdot \:3n\cdot \:2 \ \textgreater \ 2\cdot \:3^2mn$
$8m\cdot \:2n\cdot \:3 \ \textgreater \ 48mn$
$12m\cdot \:3n\cdot \:2 \ \textgreater \ 72mn$

$36mn-2\cdot \:3^2mn+48mn+72mn$

From here, group like terms
$36mn-2\cdot \:3^2mn+48mn+72mn$

$\mathrm{Add\:similar\:elements:}\:36mn+48mn+72mn=156mn$
$156mn-2\cdot \:3^2mn$

$2\cdot \:3^2mn \ \textgreater \ 2\cdot \:9mn \ \textgreater \ 18mn$

$156mn-18mn$

$\mathrm{Add\:similar\:elements:}\:156mn-18mn=138mn$

Hope this helps!

6 0

3 years ago

4(x + 2) = 2 (x – 6)

andreev551 [17]

The correct answer for this would be -10

6 0

2 years ago

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Show that d^2y/dx^2=-2x/y^5, if x^3 + y^3=1

aalyn [17]

Answer:

y³ + x³ = 1

First, differentiate the first time, term by term:

${3y^{2}.\frac{dy}{dx} + 3x^{2}} = 0 \\\\{3y^{2}.\frac{dy}{dx} = -3x^{2}} \\\\\frac{dy}{dx} = \frac{-3x^{2}}{3y^{2}} \\\\\frac{dy}{dx} = \frac{-x^{2}}{y^{2}}$

↑ we'll substitute this later (4th step onwards)

Differentiate the second time:

$3y^{2}.\frac{dy}{dx} + 3x^{2} = 0 \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + 6y(\frac{dy}{dx})^{2} + 6x = 0 \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + 6y(\frac{dy}{dx})^{2} = - 6x \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + 6y(\frac{-x^{2} }{y^{2} })^{2} = - 6x \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + 6y(\frac{x^{4} }{y^{4} }) = - 6x \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + \frac{6x^{4} }{y^{3} } = - 6x \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} = - 6x - \frac{6x^{4} }{y^{3} } \\\\$

$3y^{2}.\frac{d^{2} y}{dx^{2}} = - \frac{- 6xy^{3} - 6x^{4} }{y^{3}} \\\\\frac{d^{2} y}{dx^{2}} = - \frac{- 6xy^{3} - 6x^{4} }{3y^{2}. y^{3}} \\\\\frac{d^{2} y}{dx^{2}} = - \frac{- 2xy^{3} - 2x^{4} }{y^{5}} \\\\\frac{d^{2} y}{dx^{2}} = - \frac{-2x (y^{3} + x^{3})}{y^{5}} \\\\\frac{d^{2} y}{dx^{2}} = - \frac{-2x (1)}{y^{5}} \\\\\frac{d^{2} y}{dx^{2}} = - \frac{-2x}{y^{5}}$

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3 years ago

Answer:<br> P- 56<br> P+ 56<br> p<br> 56- P

vodomira [7]

The answer is P - 56

8 0

3 years ago

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