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earnstyle [38]
3 years ago
6

X + 3y + 2z = 7

Mathematics
2 answers:
omeli [17]3 years ago
7 0

Step-by-step explanation:

x + 3y + 2z = 7

2x − y + z = 9

-x + 4y + 5z = 14

First add the first and third equations to eliminate x.

7y + 7z = 21

Simplify:

y + z = 3

Solve for y:

y = 3 − z

Substitute into the first two equations:

x + 3(3 − z) + 2z = 7

2x − (3 − z) + z = 9

Simplify:

x + 9 − 3z + 2z = 7 → x − z = -2

2x − 3 + z + z = 9 → 2x + 2z = 12 → x + z = 6

Add the equations to eliminate z.

2x = 4

x = 2

Therefore, z = 4 and y = -1.

Ann [662]3 years ago
5 0
Just use photomath that’s easier
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Answer:

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7 0
2 years ago
Read 2 more answers
Do you think the equations (x−1)(x+3)=17+x and (x−1)(x+3)+500=517+x should have the same solution set? Why?
oksano4ka [1.4K]

Answer:

Those two pair of equations have the same solution set.

Step-by-step explanation:

There are two equations  

(x-1)(x+3)=17+x ..... (1) and  

(x-1)(x+3)+500=517+x ...... (2)

We have to check the same solution set will be there for equations (1) and (2) or not.

Now, we are going to rearrange the equation (2).

(x-1)(x+3)+500=517+x

⇒ (x-1)(x+3)=517-500+x

⇒(x-1)(x+3)=17+x

This is the same equation as equation (1).  

Therefore, there will be the same solution set for equations (1) and (2).  (Answer)

There are two equations  

(x-1)(x+3)=17+x ..... (3) and  

3(x-1)(x+3)+500=51+3x ...... (4)

We have to check the same solution set will be there for equations (3) and (4) or not.

Now, we are going to rearrange the equation (4).

3(x-1)(x+3)+500=51+3x

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This is the same equation as equation (3).  

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7 0
3 years ago
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Answer:

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Step-by-step explanation:

The sequence with constant first differences is an arithmetic sequence. The sequence of A has a common difference of -3, so is an arithmetic sequence.

6 0
3 years ago
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iren2701 [21]
All real numbers greater than or equal to -3
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4 years ago
Is 0.032 a terminating decimal
svp [43]
I don’t think it is, sorry I’m not 100% sure, good luck though
3 0
4 years ago
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