(1)
we are given

we can find for y
multiply both sides by 6


we can see that y is directly proportional to x
so, option-D........Answer
(2)
y varies inversely with x
so, we can write it as

now, we are given
y=5 when x=2.5
so, we can plug it here

and then we can solve for k


now, we can plug back

we can plug x=20

.............Answer
(3)
we are given
The current, I, in a circuit varies inversely with the resistance, R
so, we can write it as

we have R=12 when I=3
so, we can plug it

now, we can solve for k


now, we can plug back

we can plug R=6

................Answer
Answer:
Jiri is 38 years old.
Step-by-step explanation:
First, 67 - 29 = 38 and 29 + 9 = 38.
Hope this helps!
If there are 40 children aged twelve and under and x of them are under three years old, 40 - x aged three twelve years old. From the 92 people that where taken by the company on whale watching trips, 52 are over twelve years old. The equation that best show the total cost, C is
(40 - x)(36) + (52)(48) = C
Rearranging the equation gives,
x = 40 - ((C - 2496)/ 36)
Answer:
1. 13 or -13
2. -5 < y < -3
3. 6 or -6
4. 1/8 or -1/8
Step-by-step explanation:
Clear the absolute-value bars by splitting the equation into its two cases, one for the Positive case and the other for the Negative case.
The Absolute Value term is |x|
For the Negative case we'll use -(x)
For the Positive case we'll use (x)
Step 3 :
Solve the Negative Case
-(x) = 13
Multiply
-x = 13
Multiply both sides by (-1)
x = -13
Which is the solution for the Negative Case
Step 4 :
Solve the Positive Case
(x) = 13
Which is the solution for the Positive Case
Step 5 :
Wrap up the solution
x=-13
x=13
But for the case of question (2) its a different pattern..
Since this is a "less than" absolute-value inequality, my first step is to clear the absolute value according to the "less than" pattern. Then I'll solve the linear inequality.
| y + 4 | < 1
–1 < y + 4 < 1
This is the pattern for "less than". Continuing, I'll subtract 3 from all three "sides" of the inequality:
–1 – 4 < y + 4 - 4 < 1 – 4
–5 < y < -3

The solution to the original absolute-value inequality, | y + 4 | < 1 , is the interval:
