Question

9 times the sum of b and 2 is 8

Answer 1

I suppose you want to solve the following equation for b:

$9(b+2)=8$

First of all, you need to divide both sides by 9:

$b+2 = \dfrac{8}{9}$

Then, subtract 2 from both sides:

$b = \dfrac{8}{9}-2 = \dfrac{8}{9}-\dfrac{18}{9} = -\dfrac{10}{9}$