Answer:
68.26% of the parts will have lengths between 3.8 in. and 4.2 in.
Step-by-step explanation:
The lengths of a lawn mower part are approximately normally distributed
Standard deviation =
We are supposed to find What percentage of the parts will have lengths between 3.8 in. and 4.2 in . i.e. P(3.8<x<4.2)
Formula :
At x = 3.8
Z=-1
Refer the z table for p value
p value =0.1587
At x =4.2
Z=1
Refer the z table for p value
p value =0.8413
P(3.8<x<4.2)=P(x<4.2)-P(x<3.8)=0.8413-0.1587=0.6826
So, 68.26% of the parts will have lengths between 3.8 in. and 4.2 in.
Step-by-step explanation:
Angle 1 = 105 degrees (co-interior angles on a set of parallel lines)
Angle 2 = 75 degrees (corresponding angles on a set of parallel lines)
Hope you have a nice day :)
Alright, lets get started.
3 feet = 1 yard
If we cube both sides of the equation, we will get the conversion into cubic yards
So,
27 cubic feet = 1 cubic yards
So, 1 cubic feet = cubic yards
So, 360 cubic feet = cubic yards
So, 360 cubic feet = 13.33 cubic yards
13.33 cubic yards of air can it circulate per minute. : Answer
Hope it will help :)
If you add 7+7 you will get 14
Elouise and Marcus are 20 km apart. There is a lake due west of Elouise that is also 10√3 km due north of Marcus, so 22.36 km distance the bearing of Marcus from Elouise.
<h3>What is Pythagoras theorem?</h3>
According to the Pythagoras theorem, the square of the hypotenuse of a right-angled triangle equals the sum of the squares of the other two sides. The formula for this theorem is c² = a² + b², where c is the hypotenuse and a and b are the triangle's two legs. Pythagoras theory triangles are another name for these triangles.
At first assume a triangle, In the triangle, assume Elouise at the point A and Marcus at the point B, and the lake at the C point.
Given that,
Elouise and Marcus are 20 km apart (AB)
There is a lake due west of Elouise that is also 10√3 km due north of Marcus (BC)
Now, according to a Pythagoras theorem,
(AC)² + (AB)² = (BC)²
or, (AC)² = (BC)²- (AB)²
or, (AC)² = (10√3)² - (20)²
or, AC =
or, AC = 22.36 km
So, distance bearing of Marcus from Elouise is 22.36 km.
To know more about distance refer to:
brainly.com/question/13963928
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