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ra1l [238]
3 years ago
6

Please help immediately!!

Mathematics
1 answer:
zheka24 [161]3 years ago
6 0

Answer:

x=7°      y=4°

Step-by-step explanation:

7x+131=180

7x=180-131=49

x=49/7=7°

11x+y+99=180

77+y+99=180

y=180-99-77

y=4°

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the weights of a particular size of boxes of apple cinnamon cheerios are approximately normally distributed with mean weight 23.
Damm [24]

Answer:

0.15%, or 15/100 of 1%, or 3/20 of 1%

Step-by-step explanation:

68% of the data lies within 1 standard deviation of the mean (23.3 oz), or between 23.1 oz and 23.5 oz.

95% of the data lies within 2 std. dev. of the mean, or between 22.9 oz and 23.3 oz.  

99.7% of the data lies within 3 std. dev of the mean, or between 22.7 oz. and  23.1 oz.

The remaining area under the curve is 100% - 99.7%, or 0.3%,  Only half of this, or 0.15%, is to the left of 22.7 oz.


6 0
3 years ago
What is the exact distance from (−1, 4) to (6, −2)?
vladimir1956 [14]
D = √(x2 - x1)^2 + (y2 - y1)^2) = 
= √(6 + 1)^2 + (-2 - 4)^2)  =
= √ (7^2 + 6^2) = 
= √(49 + 36)  =
= √85
5 0
3 years ago
Which one does not belong? <br><br> A. 3x<br> B. 8x<br> C. 3<br> D. -5x
zalisa [80]

Answer:

i believe C does not belong because it is the only one without x

5 0
3 years ago
Factor this expression completely, then place the factors in the proper location on the grid.
andreev551 [17]

Notice that you have a difference of cubes:

\dfrac{x^3}8-\dfrac{y^3}{27}=\left(\dfrac x2\right)^3-\left(\dfrac y3\right)^3

which can be factored using the rule,

a^3-b^3=(a-b)(a^2+ab+b^2)

So,

\dfrac{x^3}8-\dfrac{y^3}{27}=\left(\dfrac x2-\dfrac y3\right)\left(\dfrac{x^2}4+\dfrac{xy}6+\dfrac{y^2}9\right)

and just to make things look nicer, we can pull out 1/6 from the first factor and 1/36 from the second to get

\dfrac{x^3}8-\dfrac{y^3}{27}=\dfrac1{216}(3x-2y)(9x^2+6xy+4y^2)

4 0
4 years ago
R(r1+r2)=r1r2 solve for R
NARA [144]
R(r+r^2)=(r)(r^2)
R^2+r^3=r^3
R^2=0
R=0
7 0
4 years ago
Read 2 more answers
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