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2 years ago

12

Need help asap please

2 answers:

Helen [10]2 years ago

4 0

Hello,
Your answer is C.
I hope this helps! :)

Gwar [14]2 years ago

3 0

Answer:

The answer is C

Step-by-step explanation:

You might be interested in

I’d appreciate the help!

Elis [28]

Answer:

$\displaystyle 1\frac{119}{250}\:liter$

$\displaystyle 7,5\:sleps$

$\displaystyle 37,3\:sleps$

Step-by-step explanation:

$\displaystyle 1\frac{119}{250} = \frac{1476}{1000}$

$\displaystyle 1\frac{1}{13} \times 7 = 7\frac{7}{13} ≈ 7,538461538 ≈ 7,5$

$\displaystyle \frac{41}{1\frac{1}{10}} = 37\frac{3}{11} ≈ 37,3$

I am joyous to assist you anytime.

4 0

2 years ago

Please see the question and solve plz

Korolek [52]

Answer:

Step-by-step explanation:

sin²β + sin²β×tan²β = tan²β

sin²β( 1 + tan²β ) = tan²β

~~~~~~~~~~~~~~~~

<u><em>sin²β + cos²β = 1 </em></u>

<u><em /></u> $\frac{sin^2\beta }{cos^2\beta }$ + $\frac{cos^2\beta }{cos^2\beta }$ = $\frac{1}{cos^2\beta }$ ⇒ tan²β + 1 = sec²β ⇔ 1 + tan²β = sec²β

~~~~~~~~~~~~~~

1 + tan²β = $\frac{1}{cos^2 \beta }$

L.H. = sin²β ( $\frac{1}{cos^2 \beta }$ ) = tan²β

R.H. = tan²β

7 0

2 years ago

Solve each inequality, and then drag the correct solution graph to the inequality.

Nesterboy [21]

The correct solution graph to the inequalities are

$4(9x-18)>3(8x+12)$ → C

$-\frac{1}{3}(12x+6) \geq -2x +14$ → A

$1.6(x+8)\geq 38.4$ → B

(NOTE: The graphs are labelled A, B and C from left to right)

For the first inequality,

$4(9x-18)>3(8x+12)$

First, clear the brackets,

$36x-72>24x+36$

Then, collect like terms

$36x-24x>36+72\\12x >108$

Now divide both sides by 12

$\frac{12x}{12} > \frac{108}{12}$

∴ $x > 9$

For the second inequality

$-\frac{1}{3}(12x+6) \geq -2x +14$

First, clear the fraction by multiplying both sides by 3

$3 \times[-\frac{1}{3}(12x+6)] \geq3 \times( -2x +14)$

$-1(12x+6) \geq -6x +42$

Now, open the bracket

$-12x-6 \geq -6x +42$

Collect like terms

$-6 -42\geq -6x +12x$

$-48\geq 6x$

Divide both sides by 6

$\frac{-48}{6} \geq \frac{6x}{6}$

$-8\geq x$

∴ $x\leq -8$

For the third inequality,

$1.6(x+8)\geq 38.4$

First, clear the brackets

$1.6x + 12.8\geq 38.4$

Collect likes terms

$1.6x \geq 38.4-12.8$

$1.6x \geq 25.6$

Divide both sides by 1.6

$\frac{1.6x}{1.6}\geq \frac{25.6}{1.6}$

∴ $x \geq 16$

Let the graphs be A, B and C from left to right

The first graph (A) shows $x\leq -8$ and this matches the 2nd inequality

The second graph (B) shows $x \geq 16$ and this matches the 3rd inequality

The third graph (C) shows $x > 9$ and this matches the 1st inequality

Hence, the correct solution graph to the inequalities are

$4(9x-18)>3(8x+12)$ → C

$-\frac{1}{3}(12x+6) \geq -2x +14$ → A

$1.6(x+8)\geq 38.4$ → B

Learn more here: brainly.com/question/17448505

8 0

1 year ago

If X = 10 cm, Y = 24 cm, and Z = 26 cm, what is the tangent of A?

omeli [17]

2.4cm is the tangent of A

6 0

2 years ago

How to do linear functions using the table ?

Ira Lisetskai [31]

Answer:

-8 = m-2+b

-2 = m-0+b

4 = m2+b

10 = m4+b

Step-by-step explanation:

You just put them in y = mx+b format

3 0

2 years ago