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Reptile [31]
3 years ago
15

Is 9.02 greater than, less than or equal to 9.020

Mathematics
2 answers:
Whitepunk [10]3 years ago
7 0
9.02 is the same as/ equal to 9.020 the extra 0 doesn't add to the value
Keith_Richards [23]3 years ago
5 0
They're the same because you can add as many zeros as you want after the decimal point and it doesn't change the value
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-78 = -6 (p - 4)i don't understand it​
iris [78.8K]
Distribution is one of the most important terms of math you need to know.

Distributing, in this case, is when you take the -6 and multiply the terms in the parenthesis.

When you do that. You’ll get -78 = -6p+24.

*Remember: a negative times a negative is always positive. A positive times a negative is always negative. If you need more help with this tip, please feel free to reply if you need any better tips and tricks.

Now, you’re going to solve -78-24 (since you switch the sign when you bring one term to the opposite of the equation).

Then you’ll have -102 = -6p

Lastly, instead of multiplying, you divide -102 by -6.

Your final answer should be 17 = p (or flip it to make it p = 17).
5 0
3 years ago
What are 3 ratios that are equivalent to 4/7 Help please
quester [9]

Answer:

8:14, 12:27, 40:70

Step-by-step explanation:

5 0
3 years ago
Create two equivalent fractons for 3/4
Sveta_85 [38]

Answer:

6/8 and 9/12

Step-by-step explanation:

You can find any by multiplying numerator and denominator by any given number. The number multiplied has to be the same for the top and the bottom

1. Number is 2

3/4 * 2/2 = 6/8 (3*2 = 6  and 4*2 = 8)

2. Number is 3

3/4*3/3 = 9/12 (3*3 = 9 and 3*4 = 12)

3 0
3 years ago
Mrs. Wingate has 10 students in her math class. The line plot shows the number of hours students spent doing homework last week.
klio [65]
A. 35 because of you look at the line plot it explains how long student are in there for and how many times a day. So you just need to figure out how many students do hw for how long and then multiply that by 10.
8 0
3 years ago
Waiting on the platform, a commuter hears an announcement that the train is running five minutes late. He assumes the arrival ti
natima [27]

Answer:

D. 91%

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Less than 15 minutes.

Event B: Less than 10 minutes.

We are given the following probability distribution:

f(T = t) = \frac{3}{5}(\frac{5}{t})^4, t \geq 5

Simplifying:

f(T = t) = \frac{3*5^4}{5t^4} = \frac{375}{t^4}

Probability of arriving in less than 15 minutes:

Integral of the distribution from 5 to 15. So

P(A) = \int_{5}^{15} = \frac{375}{t^4}

Integral of \frac{1}{t^4} = t^{-4} is \frac{t^{-3}}{-3} = -\frac{1}{3t^3}

Then

\int \frac{375}{t^4} dt = -\frac{125}{t^3}

Applying the limits, by the Fundamental Theorem of Calculus:

At t = 15, f(15) = -\frac{125}{15^3} = -\frac{1}{27}

At t = 5, f(5) = -\frac{125}{5^3} = -1

Then

P(A) = -\frac{1}{27} + 1 = -\frac{1}{27} + \frac{27}{27} = \frac{26}{27}

Probability of arriving in less than 15 minutes and less than 10 minutes.

The intersection of these events is less than 10 minutes, so:

P(B) = \int_{5}^{10} = \frac{375}{t^4}

We already have the integral, so just apply the limits:

At t = 10, f(10) = -\frac{125}{10^3} = -\frac{1}{8}

At t = 5, f(5) = -\frac{125}{5^3} = -1

Then

P(A \cap B) = -\frac{1}{8} + 1 = -\frac{1}{8} + \frac{8}{8} = \frac{7}{8}

If given the train arrived in less than 15 minutes, what is the probability it arrived in less than 10 minutes?

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{\frac{7}{8}}{\frac{26}{27}} = 0.9087

Thus 90.87%, approximately 91%, and the correct answer is given by option D.

3 0
3 years ago
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