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mote1985 [20]
4 years ago
7

56.04 + 3.07 can someone help me step by step​

Mathematics
2 answers:
Dahasolnce [82]4 years ago
7 0

Answer:

59.11

Step-by-step explanation:

Adding decimal would almost be the same as just adding, except bring down the decimal down when you finish adding.

     1

56.04

 3.07

______

59.11

First we start out on the right, 4 + 7 = 11, 1 goes down while the other 1 goes on top of the zero (on the equation). 1 + 0 + 0 = 1. 6 + 3 = 9, and 5 comes down, since its by itself.

PSYCHO15rus [73]4 years ago
4 0

Answer:

59.11

Step-by-step explanation:

56.04+3.07

59.11

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xxTIMURxx [149]

Answer:

The convergent series are;

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\sum \limits _{n = 1}^\infty \left( \dfrac{1}{10} \right) ^n

Step-by-step explanation:

A series in mathematics is the sum of a sequence of numbers to infinity

A convergent series is a series that sums to a limit

From the given options, we have;

First option

\sum \limits _{n = 1}^\infty \dfrac{2\cdot n}{n + 1}

As 'n' increases, 2·n becomes more larger than n + 1, and the series diverges

Second option

\sum \limits _{n = 1}^\infty \dfrac{n^2 - 1}{n - 2}

As 'n' increases, n² - 1, becomes more larger than n - 2, and the series diverges

Third option

\sum \limits _{n = 1}^\infty \left( \dfrac{1}{5} \right) ^n

As 'n' increases, \left( \dfrac{1}{5} \right) ^n, becomes more smaller and tend to '0', therefore, the series converges

Fourth option

\sum \limits _{n = 1}^\infty \left( \dfrac{1}{10} \right) ^n

As 'n' increases, 3 \times\left( \dfrac{1}{10} \right) ^n, becomes more smaller and tend to '0', therefore, the series converges

Fifth option

\sum \limits _{n = 1}^\infty  \dfrac{1}{10} \cdot (3) ^n

As 'n' increases, \dfrac{1}{10} \cdot (3) ^n, becomes more larger and tend to infinity, therefore, the series diverges.

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Hope I helped!

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