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AlladinOne [14]
3 years ago
14

A student needs to select 3 books from 3 different mathematics, 3 different physics and 1 history books. What is the probability

one of them is mathematics and other two are either physics or history books
Mathematics
1 answer:
Gnesinka [82]3 years ago
8 0

Answer:

Probability that one of them is mathematics and other two are either physics or history books = 0.51

Step-by-step explanation:

Given - A student needs to select 3 books from 3 different mathematics, 3 different physics and 1 history books.

To find - What is the probability one of them is mathematics and other two are either physics or history books ?

Solution -

Given that,

A student needs to select 3 books from 3 different mathematics, 3 different physics and 1 history books.

So,

Total number of books = 3 + 3 + 1 = 7

The student has to select 3 books

So, Total number of ways = ^{7} C_{3} = 35

So,

Probability that one of them is mathematics and other two are either physics or history books is -

= \frac{^{3} C_{1}. ^{4} C_{2}  }{^{7} C_{3}}

= \frac{(3)(6)}{35}

= \frac{18}{35}

= 0.51

⇒Probability that one of them is mathematics and other two are either physics or history books = 0.51

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jeyben [28]

Answer:

The inequation 6x ≥ 8x - 4 can be used to find the solution.

The solution is x ≤ 2

Step-by-step explanation:

If x represents the number then six times a number is the multiplication of x by 6, and four less than eight times the number can be written as: 8x -4

6x ≥ 8x - 4

Solving the inequation;

Subtracting 6x each side:

0 ≥ 8x - 6x -4

Summing 4 each side

4 ≥ 2x

Dividing by 2 each side

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2 greater or equal than x is the same as:

x ≤ 2

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Answer:

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b. The 95% confidence interval for the difference between the two population means is (0.58171,7.21829)

Step-by-step explanation:

a. According to the given data we have the following:

Buffalo residents mean=22.5

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Boston residents mean=18.6

Standard deviation=7.4

n=40

Hence, the point estimate is the difference of the means=22.5-18.6=3.9

The standard error=√((s1∧2/n1)+((s2∧2/n2))=√((8.4∧2/50)+(7.4∧2/40))=1.67

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b. The critical value of t at 95% confidence level and DoF=88 is 1.987

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The 95% confidence interval for the difference between the two population means is (0.58171,7.21829)

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