The difference 25(d−10)−23(d+6) is?

The material used to make a storage box costs $1.25 per square foot. The boxes have the same volume, so how much does a company

riadik2000 [5.3K]

Answer: A company saves $134.38 by choosing to make 50 of Box 2 instead of Box 1

Step-by-step explanation:

Hi, to answer this question we have to calculate the surface area of both boxes.

<em>Surface area (A) = 2wl + 2lh + 2hw, </em>

Where w is width, l is length , and h is height.

Box 1 = A = 2(6x20) + 2( 20x4) + 2 (4 x 6) =2 (120)+ 2 (80)+ 2(24) =448 in2
Box 2 = A = 2 (4x15)+ 2(15x8)+ 2(8x4) = 2(60)+2(120)+2(32)=424 in2

Since 1 inch = 0.0833333 foot

Box 1 = 448 in2 x 0,0833333 =37.34 ft2
Box 2= 424 in2 x 0,0833333 =35.19 ft2

Since the material used to make a storage box costs $1.25 per square foot.

Box 1 =37.34 ft2 x1.25 = $ 46.675
Box 2= 35.19 ft2 x 1.25 =$43.98

Since 50 of each are made:

Box 1 = $ 46.675 x50 =2,333.750
Box 2= $43.98 x50 =2,199.37

Subtracting both costs:

2,333.750(1) - 2,199.37(2) = $134.38

6 0

2 years ago

IM BEGGING FOR HELP! I AM SO CONFUSED I WILL AWARD YOU BRAINLIEST ANSWER IF YOU ANSWER THIS QUESTION PLEASE!!!! SOS!! (P.S. sorr

umka2103 [35]

32 floors
32*11=total feet from ground to top
h=297-4.4t
set 11=297-4.4t to find the time it will take since each floor is 11 ft high

8 0

2 years ago

Read 2 more answers

Polymer composite materials have gained popularity because they have high strength to weight ratios and are relatively easy and

Brums [2.3K]

Answer:

$t=\frac{51.6-48}{\frac{1.1}{\sqrt{10}}}=10.349$

$p_v =P(t_9>10.349)=1.34x10^{-6}$

If we compare the p value and the significance level given for example $\alpha=0.05$ we see that $p_v$ so we can conclude that we reject the null hypothesis, and the the actual mean is significantly higher than 48 MPa at 5% of significance.

Step-by-step explanation:

1) Data given and notation

$\bar X=51.6$ represent the sample mean

$s=1.1$ represent the standard deviation for the sample

$n=10$ sample size

$\mu_o =48$ represent the value that we want to test

$\alpha=0.05$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to determine if the mean score is higher than 48, the system of hypothesis would be:

Null hypothesis: $\mu \geq 48$

Alternative hypothesis: $\mu > 48$

We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{51.6-48}{\frac{1.1}{\sqrt{10}}}=10.349$

Calculate the P-value

First we find the degrees of freedom:

$df=n-1=10-1=9$

Since is a one-side upper test the p value would be:

$p_v =P(t_9>10.349)=1.34x10^{-6}$

Conclusion

If we compare the p value and the significance level given for example $\alpha=0.05$ we see that $p_v$ so we can conclude that we reject the null hypothesis, and the the actual mean is significantly higher than 48 MPa at 5% of significance.

5 0

3 years ago

Rewrite without parentheses and simplify (v-7)^2

Zina [86]

Your answer correct good night

8 0

2 years ago

Sam opened a money account that pays 3 % simple interest. He started the account with 7000$ and made no further deposits. When h

Novosadov [1.4K]

He kept his account open for 3 years

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2 years ago