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2 years ago

2) find the volume of the trapezoid prism 7in 6in 4in 12in

Mathematics

2 answers:

oksano4ka [1.4K]2 years ago

7 0

Answer: 228 in3 (sorry I don’t know how to do the mini number at the top)

JulsSmile [24]2 years ago

3 0

Just here to get points sorry

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An inverse variation includes the points (15,1) and (n,5). Find n

djyliett [7]

Inverse variation: y=k/x

1. plug in the values: (15,1)
1=k/15

2. solve for k

3. Now, plug in what you can for the second point: (n,5)
5=k/n (if you do the step above, you will know “k”.

4. Solve for “n”

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2 years ago

What is the yintercept of the line given by the equation below? y= 8x+7

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3 years ago

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In a simple random sample of 14001400 young people, 9090% had earned a high school diploma. Complete parts a through d below.

ratelena [41]

Answer:

(a) The standard error is 0.0080.

(b) The margin of error is 1.6%.

(c) The 95% confidence interval for the percentage of all young people who earned a high school diploma is (88.4%, 91.6%).

(d) The percentage of young people who earn high school diplomas has increased.

Step-by-step explanation:

Let p = proportion of young people who had earned a high school diploma.

A sample of n = 1400 young people are selected.

The sample proportion of young people who had earned a high school diploma is:

$\hat p=0.90$

(a)

The standard error for the estimate of the percentage of all young people who earned a high school diploma is given by:

$SE_{\hat p}=\sqrt{\frac{\hat p(1-\hat p)}{n}}$

Compute the standard error value as follows:

$SE_{\hat p}=\sqrt{\frac{\hat p(1-\hat p)}{n}}$

$=\sqrt{\frac{0.90(1-0.90)}{1400}}\\$

$=0.008$

Thus, the standard error for the estimate of the percentage of all young people who earned a high school diploma is 0.0080.

(b)

The margin of error for (1 - α)% confidence interval for population proportion is:

$MOE=z_{\alpha/2}\times SE_{\hat p}$

Compute the critical value of z for 95% confidence level as follows:

$z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96$

Compute the margin of error as follows:

$MOE=z_{\alpha/2}\times SE_{\hat p}$

$=1.96\times 0.0080\\=0.01568\\\approx1.6\%$

Thus, the margin of error is 1.6%.

(c)

Compute the 95% confidence interval for population proportion as follows:

$CI=\hat p\pm MOE\\=0.90\pm 0.016\\=(0.884, 0.916)\\\approx (88.4\%,\ 91.6\%)$

Thus, the 95% confidence interval for the percentage of all young people who earned a high school diploma is (88.4%, 91.6%).

(d)

To test whether the percentage of young people who earn high school diplomas has increased, the hypothesis is defined as:

H₀: The percentage of young people who earn high school diplomas has not increased, i.e. p = 0.80.

Hₐ: The percentage of young people who earn high school diplomas has not increased, i.e. p > 0.80.

Decision rule:

If the 95% confidence interval for proportions consists the null value, i.e. 0.80, then the null hypothesis will not be rejected and vice-versa.

The 95% confidence interval for the percentage of all young people who earned a high school diploma is (88.4%, 91.6%).

The confidence interval does not consist the null value of p, i.e. 0.80.

Thus, the null hypothesis is rejected.

Hence, it can be concluded that the percentage of young people who earn high school diplomas has increased.

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3 years ago

Hi, anyone can help with this Thanks!!

Airida [17]

Answer:

sas

Step-by-step explanation:

side angle side,

since cf and cb are the same measurement (represented by the line in the line), the angles are the same also (curves), they are congurent

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3 years ago

PLEASE HELP!!! WILL GRANT BRAINLIEST IF CORRECT, NEED NOW

Vinil7 [7]

Answer:

Step-by-step explanation:

For each equation, set x to 0. A is correct because if x=o, then y will equal 38.910.

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3 years ago