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4 years ago

18.08 3 s.f. help please

Mathematics

1 answer:

guapka [62]4 years ago

4 0

Answer:

Step-by-step explanation:

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Can you put that in english?

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3 years ago

Twice a number (z) added to 21 is equal to 9 times the number added to 7. What is the number?

pickupchik [31]

Answer:

The number is 2

Step-by-step explanation:

Twice a number (z) = 2*z = 2z

Twice a number (z) added to 21 = 2z + 21

9 times the number added to 7 = 9z + 7

9z + 7 = 2z + 21

Subtract 2z form both sides

9z - 2z + 7 = 21

7z + 7 = 21

Subtract 7 from both sides

7z = 21 - 7

7z = 14

Divide both sides by 7

z = 14/7

z = 2

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3 years ago

Part D The narrator in the video said that sometimes our observations are unreliable. What was he referring to?

atroni [7]

Answer:

The fireball was speeding up as it moves upwards, but a measurement of motion shows that isn't true, so our observations can be unreliable.

Step-by-step explanation:

Edmentum answer just wrote in my own way a little! Hope this helps you! Have a great day!

6 0

3 years ago

Read 2 more answers

PLEASE HELP ASAP!!!!!!!!!!!!!!!

LenaWriter [7]

Answer:

the answer is D

Step-by-step explanation:

y= $x^{2}$ +1

4 0

3 years ago

If cos Θ = square root 2 over 2 and 3 pi over 2 < Θ < 2π, what are the values of sin Θ and tan Θ?

KIM [24]

Answer:

The answer is

$sin(\theta)=-\frac{\sqrt{2}}{2}$

$tan(\theta)=-1$

Step-by-step explanation:

we know that

$tan(\theta)=\frac{sin(\theta)}{cos(\theta)}$

$sin^{2}(\theta)+cos^{2}(\theta)=1$

In this problem we have

$cos(\theta)=\frac{\sqrt{2}}{2}$

$\frac{3\pi}{2}$

The angle $\theta$ belong to the third or fourth quadrant

The value of $sin(\theta)$ is negative

Step 1

Find the value of $sin(\theta)$

Remember

$sin^{2}(\theta)+cos^{2}(\theta)=1$

we have

$cos(\theta)=\frac{\sqrt{2}}{2}$

substitute

$sin^{2}(\theta)+(\frac{\sqrt{2}}{2})^{2}=1$

$sin^{2}(\theta)=1-\frac{1}{2}$

$sin^{2}(\theta)=\frac{1}{2}$

$sin(\theta)=-\frac{\sqrt{2}}{2}$ ------> remember that the value is negative

Step 2

Find the value of $tan(\theta)$

$tan(\theta)=\frac{sin(\theta)}{cos(\theta)}$

we have

$sin(\theta)=-\frac{\sqrt{2}}{2}$

$cos(\theta)=\frac{\sqrt{2}}{2}$

substitute

$tan(\theta)=\frac{-\frac{\sqrt{2}}{2}}{\frac{\sqrt{2}}{2}}$

$tan(\theta)=-1$

8 0

4 years ago

Read 2 more answers