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docker41 [41]
3 years ago
14

An infinite sheet of charge, oriented perpendicular to the x-axis, passes through x = 0. It has a surface charge density ?1 = -4

.6 ?C/m2. A thick, infinite conducting slab, also oriented perpendicular to the x-axis occupiees the region between a = 2.8 cm and b = 4.5 cm. The conducting slab has a net charge per unit area of ?2 = 60 ?C/m2.
1) What is Ex(P), the value of the x-component of the electric field at point P, located a distance 6.3 cm from the infinite sheet of charge?N/C 2)
2) What is Ey(P), the value of the y-component of the electric field at point P, located a distance 6.3 cm from the infinite sheet of charge?N/C 3)
3) What is Ex(R), the value of the x-component of the electric field at point R, located a distance 1.4 cm from the infinite sheet of charge?N/C 4)
4) What is Ey(R), the value of the y-component of the electric field at point R, located a distance 1.4 cm from the infinite sheet of charge?N/C 5)
5) What is b, the charge per unit area on thesurface of the slab located at x = 4.9 cm??C/m2 6)
6) What is Ex, the value of the x-component of the electric field at a point on the x-axis located at x = 3.64 cm ?N/C 7)
7) What is ?a, the charge per unit area on the surface of the slab located at x = 2.8 cm??C/m2 8)
Mathematics
1 answer:
Dennis_Churaev [7]3 years ago
8 0
I have no clue man I’m sorry
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Naily [24]

Answer:

<em>The</em><em> </em><em>answer</em><em> </em><em>is</em><em> </em><em>x</em><em> </em><em>-</em><em> </em><em>y</em><em> </em><em>=</em><em> </em><em>7</em>

Step-by-step explanation:

<em>2x</em><em> </em><em>-</em><em> </em><em>2y</em><em> </em><em>=</em><em> </em><em>14</em><em> </em>

<em>2</em><em>(</em><em>x</em><em> </em><em>-</em><em> </em><em>y</em><em>)</em><em> </em><em>=</em><em> </em><em>14</em><em> </em>

<em>x</em><em> </em><em>-</em><em> </em><em>y</em><em> </em><em>=</em><em> </em><em>14</em><em>/</em><em>2</em>

<em>x</em><em> </em><em>-</em><em> </em><em>y</em><em> </em><em>=</em><em> </em><em>7</em><em> </em>

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7 0
2 years ago
Which of the following theorems cannot be used to prove two lines are<br> parallel?
mariarad [96]

Answer:

Option H

Step-by-step explanation:

Option F

If two lines are cut by a transversal so that a pair of corresponding angles are congruent, then the lines are parallel.

True.

Option G

If two lines are cut by a transversal so that a pair of alternate exterior angles are congruent, then the lines are parallel.

True

Option H

If two line are cut by a transversal so that a pair of vertical angles are congruent, then the lines are parallel.

Since, vertical angles don't prove the lines cut by a transversal are parallel.

So the statement is False.

Option J

If two lines are are cut by a transversal so that a pair of same side interior angles are supplementary, then the lines are parallel.

True.

6 0
3 years ago
Square ABCD is shown below.
valentina_108 [34]

Answer:

35 is the length of BE

Step-by-step explanation:

2(2x + 5) = 8x - 50

4x + 10 = 8x -50

10+50 = 8x-4x

60= 4x

15 = x

2x + 5 = length of BE equal to length of DE

2(15) +5 = BE

30 +5

35 is the length of BE

6 0
3 years ago
What is the solution to this equation? 4x^2+98=0
Bess [88]
There is no real solution

6 0
3 years ago
Three lights all go on one changes every 5 sec one every 6 sec one every 8 sec when will they all go on together
inysia [295]
In order to calculate, you need to find their LCM
LCM of 5,6 and 8 is equal to 120

So, That time will be 120 sec = 2 min.
In short, Your Final Answer would be 2 min.

Hope this helps!
3 0
3 years ago
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