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Answer:
$2.50
Step-by-step explanation:
The question asks for the total cost of a notebook and pen together. We don't need to find their individual costs in order to answer the question.
Sometimes we get bored solving systems of equations in the usual ways. For this question, let's try this.
The first equation has one more notebook than pens. The second equation has 4 more notebooks than pens. If we subtract 4 times the first equation from the second, we should have equal numbers of notebooks and pens.
(8n +4p) -4(3n +2p) = (16.00) -4(6.50)
-4n -4p = -10.00 . . . . . . . . . . . simplify
n + p = -10.00/-4 = 2.50 . . . . divide by the coefficient of (n+p)
The total cost for one notebook and one pen is $2.50.
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<em>Additional comment</em>
The first equation has 1 more notebook than 2 (n+p) combinations, telling us that a notebook costs $6.50 -2(2.50) = $1.50. Then the pen is $2.50 -1.50 = $1.00.
One could solve for the costs of a notebook (n) and a pen (p) individually, then add them together to answer the question. We judge that to be more work.
Answer:
Adding them together. x = 3/2, y = 8
Step-by-step explanation:
Adding because we want to get rid of a variable. If we add, 2x + 6x = 8x, 1/2 * y + (-1/2 * y) = 0, and 7 + 5 = 12. Adding gets rid of the y variable.
By adding we get that 8x = 12 which gives us x = 12/8 = 3/2
Substituting this back into either equation will give us y = 8.
The prime numbers on the dice are 1,2,3,5 and 7 , the theoretical probability is

, which is 62.5%, the number of prime numbers in the outcome is 15, so the experimental probability is

, which is 75%, the difference between the experimental probability and the <span>theoretical probability is 12.5%.</span>