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ASHA 777 [7]
3 years ago
9

Find the values of and y the figure given below and choose the appropriate result ABC and XYZ

Mathematics
1 answer:
Yuri [45]3 years ago
3 0

Answer:

y = 8

x = 17

Step-by-step explanation:

We can find the missing values using similarity ratio

15/30 = y/16 cross multiply expressions

30y = 240 divide both sides by 30

y = 8

Now do the same for x

15/30 = x/34 cross multiply expressions

30x = 510 divide both sides by 30

x = 17

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What is the solution to (n^-3)^6 n^4
wel

Answer:

n^{10}-18n^9+135n^8-540n^7+1215n^6-1458n^5+729n^4 is \left(n-3\right)^6n^4 in expanded form

hope it helps

4 0
3 years ago
Find the discriminant of 3x^2-10x=-2
Oksanka [162]

Answer:

76

Step-by-step explanation:

given a quadratic equation in standard form : ax² + bx + c = 0 : a ≠ 0

then the discriminant is Δ = b² - 4ac

given 3x² - 10x = - 2 ( add 2 to both sides )

3x² - 10x + 2 = 0 ← in standard form

with a = 3, b = - 10 and c = 2

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3 years ago
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3 years ago
Help solve for number 6 please !!<br> :)
Semenov [28]

Answer:

x: {-3, 5}

Step-by-step explanation:

Step 1. Find least common denominator

Step 2. Multiply missing factors on top AND bottom

Step 3. Combine like terms

Step 4. Simplify (get rid of denominator)

Step 5. Solve for x

\frac{x}{x-5} +\frac{3}{x+2} =\frac{7x}{x^2-3x-10}            LCD = x^2-3x-10   OR  (x-5)(x+2)

\frac{x}{x-5}(\frac{x+2}{x+2})  +\frac{3}{x+2}(\frac{x-5}{x-5})  =\frac{7x}{x^2-3x-10}

\frac{x(x+2)}{(x-5)(x+2)} +\frac{3(x-5)}{(x+2)(x-5)} =\frac{7x}{(x-5)(x+2)}

\frac{x(x+2)+3(x-5)}{(x-5)(x+2)} =\frac{7x}{(x-5)(x+2)}

\frac{x^2+2x+3x-15}{(x-5)(x+2)} =\frac{7x}{(x-5)(x+2)}

\frac{x^2+5x-15}{(x-5)(x+2)} =\frac{7x}{(x-5)(x+2)}

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x^2-2x-15

(x-5)(x+3)

<u>x = -3, 5</u>

8 0
3 years ago
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sp2606 [1]

Answer:

Step-by-step explanation:

OBTUSE......

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