A helicopter above the ground is descending at 3.5 m/s. It drops a package from rest (relative to the helicopter). Just before i
t hits the ground the package is falling at a rate of 13.4 m/ s relative to the ground. Find the velocity of the package relative to the helicopter.
1 answer:
We are given that helicopter is descending at 3.5 m/s and a package is dropped from helicopter.
Its speed relative to helicopter is 0, that means it is started with the same speed as helicopter that is 3.5 m/sec relative to ground.
And when it reaches ground, its speed is 13.4 m/sec relative to ground.
Packet speed relative to helicopter = packet speed - helicopter speed
= 13.4 - 3.5 = 9.9 m/sec
You might be interested in
Answer:
80 ounces
Step-by-step explanation:
5x16=80
Answer:
answer is -8
Step-by-step explanation:
the question is in which value of x this equation become -61.2
7.4x-2=-61.2 by addinng both side 2
7.4x=-61.2+2
7.4x=-59.2 ,to get the value of x divide both side by 7.4.
then x =-59.2÷7.4
x= -8
Answer:
9 x 9 x 9 x 9 x 9
Step-by-step explanation:
9^5 = 9 x 9 x 9 x 9 x 9
Answer:
9/2
Step-by-step explanation:
1. Turn the equation into a fraction: 4.5/1
2. Multiply top and bottom by two: 9/2
;