A helicopter above the ground is descending at 3.5 m/s. It drops a package from rest (relative to the helicopter). Just before i
t hits the ground the package is falling at a rate of 13.4 m/ s relative to the ground. Find the velocity of the package relative to the helicopter.
1 answer:
We are given that helicopter is descending at 3.5 m/s and a package is dropped from helicopter.
Its speed relative to helicopter is 0, that means it is started with the same speed as helicopter that is 3.5 m/sec relative to ground.
And when it reaches ground, its speed is 13.4 m/sec relative to ground.
Packet speed relative to helicopter = packet speed - helicopter speed
= 13.4 - 3.5 = 9.9 m/sec
You might be interested in
Answer:
X= 1/4 or in decimal form 0.25
T = 5
Step-by-step explanation:
For (3/8)+x=(5/8) Just do 5/8-3/8 which equals 1/4.
For t-(-5)=10 I used a calculator.
I think ur problem is missing something bc I got this
Answer:
x=17
Step-by-step explanation:
3x-24=x+10
Carry over the like terms and put them together. Make the unknowns which are x the subject.
3x-x= 24+10
2x= 34
2x= 34/2
x= 17
Answer:
A
Step-by-step explanation:
I did the math (:
Good luck
Answer:
x-intercept= (2, 0)
y-intercept= (0,-6)
