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natta225 [31]
2 years ago
11

Mike discovered that the pool in his backyard is leaking slowly. The pool holds 17,897 gallons of water, and is leaking at a rat

e of 5 gallons per day. If Mike does not replace the water that has leaked from the pool, how many gallons of water will remain in the pool after 187 days?
Mathematics
1 answer:
pishuonlain [190]2 years ago
8 0

Answer:

Gallons of water remaining = 16,962 gallons

Step-by-step explanation:

Total capacity of the pool = 17,897 gallons

Rate of leakage per day = 5 gallons

Number of days = 187 days

how many gallons of water will remain in the pool after 187 days?

Gallons of water remaining = Total capacity of the pool - (Rate of leakage per day × Number of days

= 17,897 - (5 × 187)

= 17,897 - 935

= 16,962 gallons

Gallons of water remaining = 16,962 gallons

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Answer:

a'(d) = \frac{d}{5} + \frac{3}{5}

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Step-by-step explanation:

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Replace y with a'(d)

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To do this, we prove that:

a(a'(d)) = a'(a(d)) = d

Solving for a(a'(d))

a(a'(d))  = a(\frac{d}{5} + \frac{3}{5})

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a'(a(d)) = \frac{5d - 3}{5} + \frac{3}{5}

Add fractions

a'(a(d)) = \frac{5d - 3+3}{5}

a'(a(d)) = \frac{5d}{5}

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a(a'(d)) = a'(a(d)) = d

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