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3 years ago

Which rule yields the dilation of the figure BCDE centered at the origin?

Mathematics

2 answers:

Leya [2.2K]3 years ago

7 0

B (x, y) - (0.5x,0.5y) as all four sides have halved in length

Bingel [31]3 years ago

7 0

Answer:

B (x,y) > (0.5x, 0.5y)

Step-by-step explanation:

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2 years ago

Look at the Math Notes 1.1.5 in Canvas (“Representations of a Portion”). For each diagram below, write a fraction and a percent

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3 years ago

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3 years ago

In a scale drawing of an apartment 1 centimet represents 2 3/4 feet. If the length of the kitchen is 4 1/2cm on the scale drawin

weeeeeb [17]

Answer:

12 3/8 feet

Step-by-step explanation:

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2 years ago

A gambler has a coin which is either fair (equal probability heads or tails) or is biased with a probability of heads equal to 0

yawa3891 [41]

Answer:

(a) 0.1719

(b) 0.3504

Step-by-step explanation:

For every coin the number of heads follows a Binomial distribution and the probability that x of the 10 times are heads is equal to:

$P(x)=\frac{n!}{x!(n-x)!}*p^x*(1-p)^{10-x}$

Where n is 10 and p is the probability to get head. it means that p is equal to 0.5 for the fair coin and 0.3 for the biased coin

So, for the fair coin, the probability that the number of heads is less than 4 is:

$P(x$

Where, for example, P(0) and P(1) are calculated as:

$P(0)=\frac{10!}{0!(10-0)!}*0.5^0*(1-0.5)^{10-0}=0.0009\\P(1)=\frac{10!}{1!(10-1)!}*0.5^1*(1-0.5)^{10-1}=0.0098$

Then, $P(x$ , so there is a probability of 0.1719 that you conclude that the coin is biased given that the coin is fair.

At the same way, for the biased coin, the probability that the number of heads is at least 4 is:

$P(x\geq4 )=P(4)+P(5)+P(6)+...+P(10)$

Where, for example, P(4) is calculated as:

$P(4)=\frac{10!}{4!(10-4)!}*0.3^4*(1-0.3)^{10-4}=0.2001$

Then, $P(x\geq4 )=0.3504$ , so there is a probability of 0.3504 that you conclude that the coin is fair given that the coin is biased.

7 0

3 years ago