First aquarium dimensions:
Length = 6 m.
Width = 4 m and
Height = 2 meter.
Second aquarium dimensions:
Length = 8 m.
Width = 9 m and
Height = 3 meter.
We know formula for volume of a cuboidal box = Length*Width*Height.
Plugging values of length, width and height of first aquarium in formula of volume. We get
V1 = 6*4*2 = 48 m^3.
Plugging values of length, width and height of second aquarium in formula of volume. We get
V2 = 8*9*3 = 216 m^3.
In order to find the total cubic meters of space do the sea turtles have in their habitat, we need to add both volumes.
Therefore, Total voulme of both aquarium = V1 +V2 = 48+216 = 264 m^3.
Therefore, total 264 m^3 cubic meters of space the sea turtles have in their habitat.
Answer:
A
Step-by-step explanation:
Remember that the domain is all possible x values.
Here, the highest x value is 2 and the lowest is -4, which makes A and D incorrect.
x can also be anything between 2 and -4, so B is also incorrect.
That leaves C our answer.
Answer:
Part a) The elevation of the road is 
Part b) The rise is 
Step-by-step explanation:
Part a) What is the elevation of the road to the nearest degree?
Let
y-----> the rise of the road ( vertical distance)
x ----> the run of the road (horizontal distance)
we have
y/x=1/10
we know that
The ratio y/x is equal to the tangent of the angle of the elevation of the road
Let
----> angle of the elevation of the road
Part b) If the road is two km long, how much does it rise?
using proportion
Y <_ -2x+4
(<_ is less than or equal btw)
