3 years ago

Help me pleaseeeeee..

Mathematics

1 answer:

bija089 [108]3 years ago

6 0

Y <_ -2x+4
(<_ is less than or equal btw)

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Find the equation of the graphs indicated below. Clearly specify how you obtained each value in the equation.

Vika [28.1K]

Answer:

$y=\frac{1}{2}x+2$

Step-by-step explanation:

Since, the graph of the function is a straight line, function defining this function will be a linear function.

Let the equation of the line is,

y = mx + b

where m = slope of the line

b = y-intercept

From the graph,

b = 2

And two points (0, 2) and (-2, 1) lie on this line.

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= $\frac{2-1}{0+2}$

= $\frac{1}{2}$

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y = $\frac{1}{2}x+2$

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Answer:

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Step-by-step explanation:

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3 years ago

PLEASE HELP! URGENT! <br> I don’t know how to graph this

jekas [21]

graph (-3, 5)

because you would set it equal to 0 so it would be x + 3 = 0 then subtract 3 on both sides to get x = -3

same thing with x-5

set it equal to 0 to get y - 5 = 0 then just add 5 to get y=5

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Answer:

Step-by-step explanation:

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The turning point is (3,3). The x to make the absolute value negative would be 2. The ordered pair would then be (0,3)

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