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timofeeve [1]
3 years ago
6

What is the value of

7D%20%7D%20" id="TexFormula1" title=" \frac{ {3?}^{2?} }{3 {}^{4?} } " alt=" \frac{ {3?}^{2?} }{3 {}^{4?} } " align="absmiddle" class="latex-formula">
​
Mathematics
1 answer:
ch4aika [34]3 years ago
8 0
When you do the multiplication yo get 9 for the top and get 81 for the bottom and that means to divide so when you divide 9 by 81 you get 9 it’s as simple as that.
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If a truck averages 17 miles to the gallon, how many pounds of carbon dioxide are emitted into the atmosphere when the truck tra
dimulka [17.4K]
The answer might be 13.88
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3 years ago
A computer programmer's yearly income of $82,000 is increased by 6%. What is the dollar amount of the increase, and what is her
Vinvika [58]
The new yearly income is $86920.
Convert 6% into a decimal which is 0.06.
1ST METHOD:
82000*0.06=4290
4290+82000=86920
2ND METHOD:
0.06+1=1.06
82000*1.06=86920
4 0
3 years ago
Read 2 more answers
Garth estimated the height of the door to his classroom in meters.what is a reasonable estimate?
insens350 [35]
A reasonable estimate is an educated guess made by an observer based on that person's current knowledge and following observations. For example, If Garth knew that he was 1.2 meters tall, and he observed that the door was approximately twice his own height, Garth could then make the reasonable estimate that the door is about 2.4 meters tall.
8 0
3 years ago
In a certain town, the amount of sulfur oxide in the air, S, in tons, is related to the town’s population, P, in people. The rel
Lady bird [3.3K]

Answer:

Change in sulfur oxide in the air = \frac{\textup{110010}}{\textup{S}}

Step-by-step explanation:

Data provided in the question:

Relation between the amount of sulfur oxide in the air and the population as:

S² = 110P² + 20P + 600

Population growth rate, \frac{\textup{dP}}{\textup{dt}}  = 10 people per month

Now,

change in sulfur oxide with time i.e \frac{\textup{dS}}{\textup{dt}}

differentiating the given relation with respect to time 't'

we have

2S\frac{\textup{dS}}{\textup{dt}} =  2\times110P\frac{\textup{dP}}{\textup{dt}}  + 20

at P = 100 and  \frac{\textup{dP}}{\textup{dt}}  = 10 people per month

we have

2S\frac{\textup{dS}}{\textup{dt}} = 2 × 110 × 100 × 10 + 20

or

2S\frac{\textup{dS}}{\textup{dt}} = 220020

or

\frac{\textup{dS}}{\textup{dt}} = \frac{\textup{220020}}{\textup{2S}}

or

Change in sulfur oxide in the air = \frac{\textup{110010}}{\textup{S}}

8 0
3 years ago
Tommy's mom gave him $50 for cutting their grass. He used the money to buy a game for $15.75 and two snacks that cost $1.50 each
Alborosie

Answer:

a = $17.25

Step-by-step explanation:

let the money spend on the necklace be a

we have

15.75 +1.5*2 +a + 14 = 50

-> a = 50 -15.75 -3-14

-> a = $17.25

8 0
3 years ago
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