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dedylja [7]
3 years ago
14

According to a study published by the National Institute of Health, during intercourse condom breakage rates fall between 0.4% a

nd 2.3%. Suppose that the breakage rate of Brand X is 2%. A Brand X Pleasure Pack contains 12 condoms. What is the probability that at least one of the condoms in the pack will break during intercourse
Mathematics
1 answer:
grigory [225]3 years ago
3 0

Answer:

b. 0.68

Step-by-step explanation:

trust me.

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Can you guys help me on this
WITCHER [35]

Answer: 1/4 OR 1/8

Step-by-step explanation:

the first coin can be heads which has a 1/2 chance of happening and the other coin also has a chance to get tails which is 1/2

if you add the 1/2 and the other 1/2 you can get 1/4 OR 1/8

4 0
2 years ago
Read 2 more answers
If x = 5 and 5 = y, then x = y
garri49 [273]
You are right. Transitivity means, that:
if a = b and b = c, then a = c
(here a = x, b=5 and c = y).
5 0
3 years ago
One more time!
CaHeK987 [17]
Since q(x) is inside p(x), find the x-value that results in q(x) = 1/4

\frac{1}{4} = 5 - x^2\ \Rightarrow\ x^2 = 5 - \frac{1}{4}\ \Rightarrow\ x^2 = \frac{19}{4}\ \Rightarrow \\
x = \frac{\sqrt{19} }{2}

so we conclude that
q(\frac{\sqrt{19} }{2} ) = 1/4

therefore

p(1/4) = p\left( q\left(\frac{ \sqrt{19} }{2} \right)  \right)

plug x=\sqrt{19}/2 into p( q(x) ) to get answer

p(1/4) = p\left( q\left( \frac{ \sqrt{19} }{2} \right) \right)\ \Rightarrow\ \dfrac{4 - \left(  \frac{\sqrt{19} }{2}\right)^2 }{ \left(  \frac{\sqrt{19} }{2}\right)^3 } \Rightarrow \\ \\ \dfrac{4 - \frac{19}{4} }{ \frac{19\sqrt{19} }{8}} \Rightarrow \dfrac{8\left(4 - \frac{19}{4}\right) }{ 8 \cdot \frac{19\sqrt{19} }{8}} \Rightarrow \dfrac{32 - 38}{19\sqrt{19}} \Rightarrow \dfrac{-6}{19\sqrt{19}} \cdot \frac{\sqrt{19}}{\sqrt{19}}\Rightarrow

\dfrac{-6\sqrt{19} }{19 \cdot 19} \\ \\ \Rightarrow  -\dfrac{6\sqrt{19} }{361}

p(1/4) = -\dfrac{6\sqrt{19} }{361}
3 0
3 years ago
2. (8 points) If you have n gold coins with one a fake that you know is slightly lighter, how many weighings on the pan balance
pogonyaev

Answer:

Only 1 Time

Step-by-step explanation:

Since you know that one coin is fake and that the coin is lighter than the rest , then you would only need to weigh all the coins together 1 time to ensure that you will find the fake coin. We can determine this by doing the following.

<u>Example:</u>

Lets say we have 100 coins that weigh 1 gr each. Meaning that the total weight of the 100 coins would be (100coins*1gr = 100gr) <em><u>IF</u></em> there are no fake coins in the batch.

Knowing this we can weigh the entire batch 1 time and if the total weight is less than 100gr we know that the fake coin is in that batch.

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

5 0
3 years ago
How is the number e defined?
Leviafan [203]
It can be defined as a positive..
it is also a inverse function to the natural exponential function 
i hope that helps 
8 0
3 years ago
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