Question

Consider a roulette wheel consisting of 38 numbers 1 through 36, 0, and double 0. If Smith always bets that the outcome will be one of the numbers 1 through 12, what is the probability that a. Smith will lose his first 5 bets

Answer 1

Answer:

0.003

Step-by-step explanation:

Given: A roulette wheel consists of 38 numbers 1 to 36, 0, and double 0.

Smith bets that the outcome will be one of the numbers 1 through 12.

To find: probability that Smith will lose his first 5 bets

Solution:

Probability refers to chances of occurrence of some event.

Probability = Number of favourable outcomes/Total number of outcomes

Total number outcomes = 38

As Smith bets that the outcome will be one of the numbers 1 through 12, number of favourable outcomes is equal to 12.

So,

probability that Smith will loss his first bet = $\frac{12}{38}=\frac{6}{19}$

Therefore,

Probability that Smith will lose his first 5 bets = $(\frac{6}{19} )^5=0.003$