Which transformations can be used to map a triangle with vertices A(2, 2), B(4, 1), C(4, 5) to A’(–2, –2), B’(–1, –4), C’(–5, –4
jek_recluse [69]
Notice that every pair of point (x, y) in the original picture, has become (-y, -x) in the transformed figure.
Let ABC be first transformed onto A"B"C" by a 90° clockwise rotation.
Notice that B(4, 1) is mapped onto B''(1, -4). So the rule mapping ABC to A"B"C" is (x, y)→(y, -x)
so we are very close to (-y, -x).
The transformation that maps (y, -x) to (-y, -x) is a reflection with respect to the y-axis. Notice that the 2. coordinate is same, but the first coordinates are opposite.
ANSWER:
"<span>a 90 clockwise rotation about the origin and a reflection over the y-axis</span>"
Answer:
d/2 = r if you are talking about circles, if that's the case then the r would be 5
Your vertex is (8,7)
First find the x intercept
-2/2a
X = 16/2
X = 8
Substitute the value x and solve for y
Youd get 7
Hence
(8,7)
Answer:
Below.(0)
Step-by-step explanation:
Step by step.
So we know that the tens digit is after the ones place so?
The ones are 6. That means the digit in the tens place is
0.
you answer is 10 hope this help[s :D