15 POINT QUESTION! Multiply and simplify. (4x−2)(3x^2−2x+1)

2 answers:

7 0

To answer this, first, you need to multiply the first bracket to the second bracket. Then, it will show like this: 4x(3x^2)-4x(2x)+4x(1)-2(3x^2)-2(-2x)-2(1)= 12x^3-8x^2+4x-6x^2+4x-2.
Then simplify them by adding or subtracting the same objects (same exponents and same variables). If they don't have the same objects, just let them be.
The final answer will be: -12x^3-14x^2+8x-2

Crazy boy [7]3 years ago

6 0

The correct answer is 12x³-14x²+8x-2.

Explanation:
We use the distributive property:
4x*3x² - 4x*2x + 4x*1 - 2*3x² - 2*(-2x) - 2*1 = 12x² - 8x² + 4x - 6x² + 4x - 2.

Combining like terms, we have 12x³-14x²+8x-2.

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Norma-Jean [14]

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3 years ago

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sladkih [1.3K]

D is halfway between A and B

so the coordinates of D are (2,2)

E is halfway between A and C so the coordinates of E are (-1,1)

now you need to find the gradient/slope of DE and BC using the formula:

$\frac{y2 - y1}{x2 - x1}$

<h3>Gradient of DE: </h3>

SUB IN COORDINATES OF D AND E

$\frac{1 - 2}{ - 1 - 2}$

therefore the gradient of DE is 1/3.

<h3>Gradient of BC:</h3>

SUB IN COORDINATES OF B AND C

 $\frac{ - 2 - 0}{ - 3 - 3}$ 

therefore the gradient of BC is -2/-6 which simplifies to 1/3.

<h3>therefore, BC and DE are parallel as they both have a gradient/slope of 1/3 and parallel lines have the same gradient</h3>

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3 years ago

Solve for the equation, show all your work. This is an absolute value equation. You need to show both equations and the work for

VMariaS [17]

Answer:

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