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3 years ago

After 8 hours of snow, the

1 answer:

4 0

Answer: -21.125 or -21 1/8 degrees

Explanation: Divide the number of degrees (-169) by the amount of time it was snowing (8) to get the answer (-21.125).

-169÷8=-21.125

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What equation (s) must be entered in a graphing utility to obtain the graph of x^(2)+y^(2)=25

patriot [66]

Answer:

x^2+y^2=25

Step-by-step explanation:

For my graphing utility, entering the given equation will generate the required graph. (The parentheses are not needed, but do no harm.)

7 0

4 years ago

Please help!

Gemiola [76]

The derivative of $f(x) = 2\cdot x^{2}-9$ is $f'(x) = 4\cdot x$ .

In this exercise we must apply the definition of derivative, which is described below:

$f'(x) = \lim_{x \to 0} a_n \frac{f(x+h)-f(x)}{h}$ (1)

If we know that $f(x) = 2\cdot x^{2}-9$ , then the derivative of the expression is:

$f'(x) = \lim_{h \to 0} \frac{2\cdot (x+h)^{2}-9-2\cdot x^{2}+9}{h}$

$f'(x) = 2\cdot \lim_{h \to 0} \frac{x^{2}+2\cdot h\cdot x + h^{2}-2\cdot x^{2}}{h}$

$f'(x) = 2\cdot \lim_{h \to 0} 2\cdot x + h$

$f'(x) = 4\cdot x$

The derivative of $f(x) = 2\cdot x^{2}-9$ is $f'(x) = 4\cdot x$ .

We kindly invite to check this question on derivatives: brainly.com/question/23847661

4 0

3 years ago

Which one of these equations match the graph?

beks73 [17]

Answer:

C y = 2sin(1/3) x

Step-by-step explanation:

It's a sin function since y = 0 at x = 0

The amplitude is 2

There are 2 cycles in 12π

so the period is 6π

The x coefficent is then 2π/6π = 1/3

Answer

C y = 2sin(1/3) x

3 0

3 years ago

50 POINTS!! find area

just olya [345]

Answer: $29in^2$

Step-by-step explanation:

The figure is formed by a square, a parallelogram and a rectangle.

Then, the area of the figure will be the sum of the area of the square, the area of the parallelogram and the area of the rectangle.

The area of the square is:

$Area_1=side^2=(2in)^2=4in^2$

The area of the parallelogram is:

$Area_2=base*height=(5in)(3in)=15in^2$

The area of the rectangle is:

$Area_3=length*width=(5in)(2in)=10in^2$

Therefore, the area of the figure is:

$Area_T=A_1+A_2+A_3\\Area_T=4in^2+15in^2+10in^2\\Area_T=29in^2$

6 0

3 years ago

Read 2 more answers

The graph makes it appear that there are how many times as many students per teacher at North HS as there are at

Serggg [28]

Answer:

5 times

Step-by-step explanation:

Using visual inspection, the bar of North HS is 5 times longer Than the bar of West HS.

The gtids are of equal size, West HS occupies one portion of the grid, while North HS occupies 5 portions of the grid

5 portions / 1 portion = 5

Hence, North HS according to the graph is 5 times West HS

8 0

3 years ago