7.6 - 5(k + 1.1) = 1.6

7.6 - 5(k + 1.1) - 7.6 = 1.6 - 7.6

-5(k +1.1) = -6

-5(k + 1.1) -6
-------------- = ---------
-5 -5

k + 1.1 = 6
-----
5

k + 1.1 - 1.1 = 6
----- - 1.1
5

k = 0.1

8 0

3 years ago

An Air Conditioner uses 850 Watts of electricity and local emissions from electricity produce 1.37 pounds of CO2 per kWh. If you

Zina [86]

Answer: 6,987,000 pounds fo CO₂ per kWh.

Step-by-step explanation: Quilowatt-hour (kWh) is a unit of energy that measures the amount of energy expended in 1 hour.

The AC uses 850 Watts, which in kW is 850,000 kW

If you leave the AC on for 6 hours, it will consume

850,000(6) = 5,100,000 kWh

Eletricity produces 1.37 pounds of CO₂ per kWh, then in 5,100,000 kWh:

1.37 $\frac{pounds}{kWh}$ .(5,100,000kWh) = 6,987,000 pounds

If you open a window for 6 hours, you would keep 6,987,000 pounds of CO₂ for entering the atmosphere.

7 0

3 years ago