Answer:
Step-by-step explanation:
For this qestion u will do step b
Answer:
a. 85 m
b. 96 cm
Step-by-step explanation:
Work for (a.)
- 95 x 2 = 190.
- 360 - 190 = 170
- 170 ÷ 2 = 85
- Final Answer: 85 m
Work for (b.)
- 58 x 2 = 116
- 5568 ÷ 58 = 96
- To make sure: 96 x 58 = 5568
- Final Answer: 96 cm
We can find distances
Length of AB:
A=(-2,-2)
so, x1=-2 , y1=-2
B=(4,-2)
so, x2=4 , y2=-2
now, we can use distance formula
![d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%28x_2-x_1%29%5E2%2B%28y_2-y_1%29%5E2%7D)
now, we can plug values
![AB=\sqrt{(4-(-2))^2+((-2)-(-2))^2}](https://tex.z-dn.net/?f=AB%3D%5Csqrt%7B%284-%28-2%29%29%5E2%2B%28%28-2%29-%28-2%29%29%5E2%7D)
![AB=6](https://tex.z-dn.net/?f=AB%3D6)
Length of CB:
C=(4,6)
so, x1=4 , y1=6
B=(4,-2)
so, x2=4 , y2=-2
now, we can use distance formula
![d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%28x_2-x_1%29%5E2%2B%28y_2-y_1%29%5E2%7D)
now, we can plug values
![CB=\sqrt{(4-(4))^2+((-2)-(6))^2}](https://tex.z-dn.net/?f=CB%3D%5Csqrt%7B%284-%284%29%29%5E2%2B%28%28-2%29-%286%29%29%5E2%7D)
![CB=8](https://tex.z-dn.net/?f=CB%3D8)
Length of AC:
A=(-2,-2)
so, x1=-2 , y1=-2
C=(4,6)
so, x2=4 , y2=6
now, we can use distance formula
![d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%28x_2-x_1%29%5E2%2B%28y_2-y_1%29%5E2%7D)
now, we can plug values
![AC=\sqrt{(4-(-2))^2+((6)-(-2))^2}](https://tex.z-dn.net/?f=AC%3D%5Csqrt%7B%284-%28-2%29%29%5E2%2B%28%286%29-%28-2%29%29%5E2%7D)
![AC=10](https://tex.z-dn.net/?f=AC%3D10)
Length of DE:
D=(5,7)
so, x1=5 , y1=7
E=(5,1)
so, x2=5 , y2=1
now, we can use distance formula
![d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%28x_2-x_1%29%5E2%2B%28y_2-y_1%29%5E2%7D)
now, we can plug values
![DE=\sqrt{(5-(5))^2+((1)-(7))^2}](https://tex.z-dn.net/?f=DE%3D%5Csqrt%7B%285-%285%29%29%5E2%2B%28%281%29-%287%29%29%5E2%7D)
![DE=6](https://tex.z-dn.net/?f=DE%3D6)
Length of EF:
E=(5,1)
so, x1=5 , y1=1
F=(13,1)
so, x2=13 , y2=1
now, we can use distance formula
![d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%28x_2-x_1%29%5E2%2B%28y_2-y_1%29%5E2%7D)
now, we can plug values
![EF=\sqrt{(13-(5))^2+((1)-(1))^2}](https://tex.z-dn.net/?f=EF%3D%5Csqrt%7B%2813-%285%29%29%5E2%2B%28%281%29-%281%29%29%5E2%7D)
![EF=8](https://tex.z-dn.net/?f=EF%3D8)
Length of DF:
D=(5,7)
so, x1=5 , y1=7
F=(13,1)
so, x2=13 , y2=1
now, we can use distance formula
![d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%28x_2-x_1%29%5E2%2B%28y_2-y_1%29%5E2%7D)
now, we can plug values
![DF=\sqrt{(13-(5))^2+((1)-(7))^2}](https://tex.z-dn.net/?f=DF%3D%5Csqrt%7B%2813-%285%29%29%5E2%2B%28%281%29-%287%29%29%5E2%7D)
![DF=10](https://tex.z-dn.net/?f=DF%3D10)
now, we can compare them
![AB=DE=6](https://tex.z-dn.net/?f=AB%3DDE%3D6)
![CB=EF=8](https://tex.z-dn.net/?f=CB%3DEF%3D8)
![AC=DF=10](https://tex.z-dn.net/?f=AC%3DDF%3D10)
now, we can draw both triangles
Since, sides of both triangles are equal
so, by using SSS rule
triangle ABC and triangle DEF are congruent
so, this is TRUE........Answer
Answer:
Function app has a vertical asymptote at x=-1
Function f has a hole at x= -3
The end behaviour of function F is described by in oblique asymptote.
Answer:
35 degree celcuis
Step-by-step explanation: